Two angles are said to be complementary, if the sum of the measures of the to angles is equal to 90 degrees.
Thus, given that HFG is complementary to ACB, them mHFG + mACB = 90 degrees.
From the figure, given that the line from point F meats line CE at point P, then HFG = CFP.
But mCFE = 90 degrees and mCFE = mCFP + mPFE
Also PFE = DFH
Thus, mCFE = mCFP + mPFE = mHFG + mDFH = 90 degrees
Recall that mHFG + mACB = 90 degrees
Thus, mHFG + mACB = mHFG + mDFH
Therefore, mACB = mDFH.
Answer is D. Add the equations in order to solve for the first variable. Plug this value into the other equations in order to solve for th remaining varables
144 degrees, q=s, so 3a=4a-12. a=12, and 12*12= 144
Answer:
2
Step-by-step explanation:
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A composition of reflections across two intersecting lines is a rotation.
I hope helped ^^