Two angles are said to be complementary, if the sum of the measures of the to angles is equal to 90 degrees.
Thus, given that HFG is complementary to ACB, them mHFG + mACB = 90 degrees.
From the figure, given that the line from point F meats line CE at point P, then HFG = CFP. But mCFE = 90 degrees and mCFE = mCFP + mPFE Also PFE = DFH
%/100 X is/of 177 IS 60% of the students. so you put 60/100 and multiply 177/X 177X100=17700. Now divide that by 60 and you come up with 28.33. This obviously is not the answer so you add 28 (does not round up to 29) to 177 and you get 205.
