FALSE! You would still need to complete, just in case they accepted
Answer:
An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about 2 years.
Explanation:
Given;
orbital period of 3 years, P = 3 years
To calculate the years of an orbital with a semi-major axis, we apply Kepler's third law.
Kepler's third law;
P² = a³
where;
P is the orbital period
a is the orbital semi-major axis
(3)² = a³
9 = a³
a = ![a = \sqrt[3]{9} \\\\a = 2.08 \ years](https://tex.z-dn.net/?f=a%20%3D%20%5Csqrt%5B3%5D%7B9%7D%20%5C%5C%5C%5Ca%20%3D%202.08%20%5C%20years)
Therefore, An asteroid that has an orbital period of 3 years will have an orbital with a semi-major axis of about 2 years.
Answer:
W = 819152 J = 819.15 KJ
Explanation:
The work done by Juri can be given by the following formula:

where,
W = Work done = ?
F = Force = 200 N
d = distance = 5 km = 5000 m
θ = angle to horizontal = 35°
Therefore,
W = (200 N)(5000 m)Cos 35°
<u>W = 819152 J = 819.15 KJ</u>
Answer:
Decrease the charge of one of the particles
Infrared light because it is barely able to be seen