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larisa86 [58]
4 years ago
9

Which ph range is ideal for nitrogen in corn crops

Chemistry
1 answer:
labwork [276]4 years ago
6 0
The desirable soil pH for corn ranges from 5.8 to 7.0.
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Help asappppp quickly only right answers aloud
ivann1987 [24]

Answer:

Inference

Explanation:

A conclusion reached on the basis of evidence and reasoning is called an inference.

8 0
3 years ago
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It is the balance between thermal energy and intermolecular forces that determines the state of matter of any substance at room
ExtremeBDS [4]

Answer:

The correct option is;

2) Thermal energy increases by a factor of R

Explanation:

The equipartition energy theorem states that when molecules are in a state of thermal equilibrium, particles within the system posses equal average energy with each degree of freedom which can be known as energy due to a state of having a particular temperature or thermal energy given by the relation

E_{th} = Kinetic energy of translation + Kinetic energy of rotation + Energy of vibration

For a mono-atomic gas, E_{th} = 3/2·n·R·T

For a diatomic gas, E_{th} = 5/2·n·R·T

For a solid element, E_{th} = 3·n·R·T

Therefore, as the temperature is doubled, the thermal energy increases by a factor of R.

5 0
3 years ago
Hello!
blondinia [14]

Answer:

[CO]=[Cl_2]=0.01436M

[COCl_2]=0.00064M

Explanation:

Hello there!

In this case, according to the given chemical reaction at equilibrium, we can set up the equilibrium expression as follows:

K=\frac{[CO][Cl_2]}{[COCl_2]}

Which can be written in terms of x, according to the ICE table:

0.32=\frac{x^2}{0.015M-x}

Thus, we solve for x to obtain that it has a value of 0.01436 M and therefore, the concentrations at equilibrium turn out to be:

[CO]=[Cl_2]=0.01436M

[COCl_2]=0.015M-0.01436M=0.00064M

Regards!

5 0
3 years ago
Calculate the ph of the solution resulting from the addition of 85.0 ml of 0.35 m hcl to 30.0 ml of 0.40 m aniline (c6h5nh2). kb
stiv31 [10]

Answer:

pH = 0.81

Explanation:

HCl reacts with aniline, thus:

C₆H₅NH₂ + HCl → C₆H₅NH₃⁺ + Cl⁻

Moles of HCl are:

0.085L × (0.35mol HCl / L) = <em>0.02975mol HCl</em>

Moles of aniline are:

0.030L × (0.40mol HCl / L) = <em>0.012mol aniline</em>

Thus, after reaction, will remain:

0.02975mol - 0.012mol = <em>0.01775mol HCl</em>

Moles of HCl in solution are equal to moles of H⁺, thus, moles of H⁺ are: <em>0.01775mol H⁺</em>

As total volume is 85.0mL + 30.0mL = 115.0mL ≡ <em>0.115L</em>

0.01775mol / 0.115L = 0.1543M

pH of solution = -log[H⁺]

pH = -log 0.1543M

<em>pH = 0.81</em>

<em></em>

3 0
3 years ago
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What front involves three air masses?<br> Please don't guess, give an accurate answer
dmitriy555 [2]

Answer:

It is an Occluded front

3 0
3 years ago
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