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Crazy boy [7]
3 years ago
9

1. Coal gasification consists of the chemical transformation of solid coal into gas. The heating values of coal differ, but the

higher the heating value, the higher the value of the gas produced (which is essentially methane, carbon monoxide, hydrogen, etc.). The following coal has a reported heating value of 29,770 KJ/Kg as received. Assuming that this is the gross heating value, calculate the net heating value.
Chemistry
1 answer:
creativ13 [48]3 years ago
3 0

Complete question:

Coal gasification consists of the chemical transformation of solid coal into gas. The heating values of coal differ, but the higher the heating value, the higher the value of the gas produced (which is essentially methane, carbon monoxide, hydrogen, etc.). The following coal has a reported heating value of 29,770 KJ/Kg as received. Assuming that this is the gross heating value, calculate the net heating value.. Component__________Percent  C___________________71

H2__________________5.6

N2__________________1.6

S____________________2.7

Ash__________________6.1

O2___________________13

Answer:

LHV = 28478.8 KJ/kg

Explanation:

The gross heating value is also the higher heating value (HHV), while the net heating value is the lower heating value (LHV).

This involves the conversion from higher heating value (HHV) to lower heating value(LHV).

Let's use the formula:

LHV = HHV - 0.212H - 0.0245M - 0.008A

We are given

HHV = 29,770 KJ/kg = 29.770MJ/kg

H = hydrogen% =5.6%

A = oxygen% = 13%

M = 0

Substituting the figures in the formula, we have:

LHV = 29.770 - 0.212*5.6 - 0.0245*0 - 0.008*13

= 29.770 - 1.1872 - 0 - 0.104

= 28.4788 MJ/kg

= 28478.8 KJ/kg

LHV = 28478.8 KJ/kg

The net heating value, LHV = 28478.8 KJ/kg

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How many grams of lead(II) sulfate (303 g/mol) are needed to react with sodium chromate (162 g/mol) in order to produce 0.162 kg
Afina-wow [57]

Answer : The mass of PbSO_4 needed are, 1.515 grams.

Explanation :

First we have to calculate the mole of PbCrO_4.

\text{Moles of }PbCrO_4=\frac{\text{Mass of }PbCrO_4}{\text{Molar mass of }PbCrO_4}=\frac{0.162g}{323g/mole}=0.005mole

Now we have to calculate the moles of PbSO_4.

The balanced chemical reaction will be,

PbSO_4+Na_2CrO_4\rightarrow PbCrO_4+Na_2SO_4[tex]From the balanced chemical reaction, we conclude thatAs, 1 mole of [tex]PbCrO_4 produced from 1 mole of PbSO_4

So, 0.005 mole of PbCrO_4 produced from 0.005 mole of PbSO_4

Now we have to calculate the mass of PbSO_4

\text{Mass of }PbSO_4=\text{Moles of }PbSO_4\times \text{Molar mass of }PbSO_4

\text{Mass of }PbSO_4=0.005mole\times 303g/mole=1.515g

Therefore, the mass of PbSO_4 needed are, 1.515 grams.

6 0
3 years ago
Some oxides are given below. (i)Na2O (ii)NO2 (iii) CO2 (iv) MgO a) Which are the basic oxides among these? b) What is the name o
umka2103 [35]
<h3>Further explanation</h3>

Basic oxides ⇒ metal(usually alkali/alkaline earth) +O₂

L + O₂ ⇒ L₂O

L + O₂ ⇒ LO

Dissolve in water becomes = basic solution

L₂O+H₂O⇒ 2LOH

LO + H₂O⇒ L(OH)₂

So the basic oxides : Na₂O and MgO

Na₂O + H₂O⇒NaOH

MgO +H₂O⇒Mg(OH)₂

The aqueous solution of CO₂(dissolve in water)

CO₂ + +H₂O⇒ H₂CO₃(carbonic acid)

5 0
3 years ago
Find the no. of atoms present in 40g of nitrogen gas at STP?
nika2105 [10]

Answer:

8.60 * 10^{23} atoms N2

Explanation:

We want to convert grams to moles and then moles to atoms.

First, we convert grams of nitrogen gas (which is N2) to moles. To do so, we need the molar mass of N2, which is just 14.01 * 2 = 28.02 g.

40 g N2 * \frac{1 mol N2}{28.02 g N2} = 1.43 mol N2

Now, we need to convert moles to atoms by using Avogadro's number, which is 6.022*10^{23}:

1.43 mol N2 * \frac{6.022*10^{23} atoms N2 }{1 mol N2} = 8.60 * 10^{23} atoms N2

Thus, the answer is 8.60 * 10^{23} atoms N2.

6 0
3 years ago
What kind of frog is this!?
Yanka [14]
This kind of frog is an anaxyrus fowleri
4 0
3 years ago
How mant grams are there in 7.15 x 10^24 molecules of water?
worty [1.4K]

Answer:

B. 214.02

Explanation:

1 mol of water weighs 18.015 gm and contains 6.023 × 10²³ molecules

From question, We have 7.15 × 10²⁴ molecules

Dividing we get (7.15 × 10 ²⁴) ÷ ( 6.023 × 10²³) = 11.871 molecules

Now, Weight of water = 11.871 × 18.015 = 213.85 which is nearer to option B

4 0
2 years ago
Read 2 more answers
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