If that is your picture, then the answer is that
Geometry A is trigonal planarand Geometry B is trigonal pyramidal
Earth's outer core is a fluid layer about 2,400 km (1,500 mi) thick and composed of mostly iron and nickel that lies above Earth's solid inner core and below its mantle. Its outer boundary lies 2,890 km (1,800 mi) beneath Earth's surface. ... Unlike the inner (or solid) core, the outer core is liquid.
10) In order to find the conjugate acid of a chemical you just add a hydrogen to the chemical.
examples: the conjugate acid of Cl⁻ is HCl, the conjugate acid of PO₄³⁻ is HPO₄²⁻, the conjugate acid of NH₃ is NH₄⁺, the conjugate acid of HCO₃⁻ is H₂CO₃, and the conjugate acid of H₂O is H₃O⁺
To find the conjugate base of a chemical you just reverse that process (take away a hydrogen).
examples: the conjugate base of H₂SO₄ is HSO₄⁻, the conjugate base of CH₃COOH is CH₃COO⁻, the conjugate base of H₃PO₄ is H₂PO₄⁻, and the conjugate base of H₂O is OH⁻.
When you identify conjugate acids and bases in a reaction you look to see what lost a proton and what gained a proton. The chemical that gave up the proton acted as an acid and produced a conjugate base while the chemical that accepted a proton produced a conjugate acid.
Example: HCl+NaOH⇒NaCl+H₂O The acid is HCl and its conjugate base is Cl⁻ while NaOH was the base and H₂O is the conjugate acid. (you can ignore the sodium since it is a spectator ion).
11) When completing acid base reactions, need to identify the acid and the base since the acid will give a proton the base creating a conjugate base of the acid and conjugate acid of the base. (You need to balance the equation after you determine what the products will be)
example: H₂SO₄+2NaOH⇒Na₂SO₄+2H₂O (SO₄²⁻ is the conjugate base of HSO₄⁻ which is the conjugate base of H₂SO₄. HSO⁻ is created with the first NaOH molecule and then SO₄⁻ is created with the second NaOH.)
12) All acid base reaction form a salt consisting of the cation from the base and anion from the acid.
examples: NaCl could have come from NaOH reacting with HCl. K₃PO₄ could have come from KOH and H₃PO₄.
13) I don't really know how you are supposed to solve it with out knowing the Ka value of H₂S. H₂S is a weak acid and therefore will not dissociate completely in water so the only way of being able to find the concentration of H⁺ ions that dissociate is knowing the Ka value of H₂S and using ice tables. (Ka=[H⁺][A⁻]/[HA] and is basically the equilibrium constant for the acid when put into water where A⁻ is the conjugate base and HA is the acid).
14) Ca(OH)₂ is a strong base and will therefore dissociate completely in water. That means that when you find the concentration of OH⁻ in solution you can multiply that by the volume of the solution (in liters) to find the number of moles of OH⁻. Then you can divide that by 2 to find the number of moles of Ca(OH)₂ needed. pOH=14-pH which means that pOH=4.2. [OH⁻]=10^-pOH which means [OH⁻]=6.3x10^-5 M. 6.3x10^-5Mx3.00L=1.89x10^-4mol OH⁻ which means that (1.89x10^-4)/2=9.46x10^-5mol Ca(OH)₂.
I hope this helps. Let me know if anything is unclear.
