Answer:
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Step-by-step explanation:
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Answer: There are no real solutions.
Step-by-step explanation:
We have the equation:
x = y^2
y = x + 3/2
To solve this, we can start by noticing that x is already isolated in the first equation, then we can replace it in the second equation to get:
y = y^2 + 3/2
And now we can rewrite this as:
y^2 - y + 3/2 = 0
This is a quadratic equation, and the solutions can be calculated with Bhaskara's equation, the solutions are:
We have a negative number inside the square root, this means that the solutions are complex numbers.
Then we can conclude that the system of equations has no real solutions.
Answer:
y= 1.5x + 6; $57
Step-by-step explanation:
1.5(34) = 51
51 + 6 = 57
The derivative of a function may be used to determine whether the function is increasing or decreasing on any intervals in its domain. If f′(x) > 0 at each point in an interval I, then the function is said to be increasing on I. f′(x) < 0 at each point in an interval I, then the function is said to be decreasing on I.
Answer:
b=11.6m
Step-by-step explanation:
If this is a right triangle;
a^2+b^2=c^2
A and B are both LEGS, while C is the HYPOTENUSE
(8.7^2)+b^2=(14.5^2)
b^2=(14.5^2)-(8.7^2)
b^2=134.56
b=plus or minus 11.6
Because length can't be negative, it's +11.6
