Question

Class

Answer 1

Answer:

Problem 1: C 67 cm

Problem 2: 17 cm

Step-by-step explanation:

Problem 1:

Use the Pythagorean theorem to find the length of the hypotenuse.

a^2 + b^2 = c^2

(16 cm)^2 + (23 cm)^2 = c^2

256 cm^2 + 529 cm^2 = c^2

c^2 = 785 cm^2

c = 20 cm

perimeter = 16 cm + 23 cm + 28 cm

perimeter = 67 cm

Answer: C 67 cm

Problem 2:

The diagonal of a rectangle divides the rectangle into two congruent right triangles. We know the width of the rectangle which is a leg of a right triangle. We know the diagonal which is the hypotenuse of the right triangle. We can find the other leg of the right triangle which is the other side of the rectangle.

Pythagorean theorem:

a^2 + b^2 = c^2

a^2 = c^2 - b^2

a^2 = (6.5 ft)^2 - (2.5 ft)^2

a^2 = 42.25 ft^2 - 6.25 ft^2

a^2 = 36 ft^2

a = 6 ft

The other leg of the right triangle has measure 6 ft. That is the length of the rectangle.

perimeter = 2(length + width)

perimeter = 2(6 ft + 2.5 ft)

perimeter = 2(8.5 ft)

perimeter = 17 ft

Answer 2

Answer:

C.67

Step-by-step explanation:

Use the Pythagorean Theorem to solve this. First find the missing side. 23 squared plus 16 squared. Which equals 785 then you just find the square of that and it is 67.