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Oliga [24]
4 years ago
10

How would you measure the potential difference across a resistor?

Physics
2 answers:
AleksandrR [38]4 years ago
7 0
The answer to your question is A.
andrew-mc [135]4 years ago
3 0
Right answer of your questions is A
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In this experiment, you will use a track and a toy car to explore the concept of movement. You will measure the time it takes th
LenKa [72]
A question you can gather from this experiment is figuring out the distance traveled by the car, and how far it went. A simple solve of X equation could be used.
7 0
4 years ago
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A car is traveling down the highway cruise control at 50m/s (this means its is traveling with a constant velocity NOT accelerati
lawyer [7]

Given parameters:

Speed of car = 50m/s

Time of travel = 5minutes (300s)

Unknown;

Distance of travel = ?

To solve this problem, we need to understand how speed relates with distance and time.

 Speed is a physical quantity. It is the distance traveled divided by time taken.

                Speed  = \frac{distance}{time}

   So,

                Distance  =  speed x time

Input the parameters and solve for the distance;

               Distance  = 50m/s x 300s

               Distance  = 15000m

The distance covered during this time interval and speed is 15000m

3 0
3 years ago
What is the repulsive force between two pith balls that are 10.0 cm apart and have equal charges of -40.0 NC?
galina1969 [7]

Answer:

So the repulsive force between the pith ball will be 1.44\times 10^{-3}N

Explanation:

We have given that the pith ball have the equal charge q = -40 nC =-40\times 10^{-9}C

Distance between the charges = 10 cm =0.1 m

According to coulombs law F=\frac{KQ_1Q_2}{R*2}

F=\frac{9\times 10^9\times -40\times 10^{-9}\times -40\times 10^{-9}}{0.1^2}=1440000\times 10^{-9}=1.44\times 10^{-3}N

So the repulsive force between the pith ball will be 1.44\times 10^{-3}N

5 0
3 years ago
Given a wind turbine with blades that sweep out a 10 m diameter circle, and a wind speed of 2 m/s, approximately what is the max
Mars2501 [29]

Answer:

223.55 W

Explanation:

v = Velocity of wind = 10 m/s

r = Radius of circle = 5 m

S = Swept area

\rho = Density of air = 1.2 kg/m³

C_p = Power coefficient = 0.593

P=C_p\frac {1}{2}}\rho Sv^{3}\\\Rightarrow P=0.593\times \frac{1}{2}1.2 \pi \times 5^2\times 2^{3}\\\Rightarrow P=223.55\ W

The maximum possible power that can be produced by the turbine is 223.55 W

8 0
4 years ago
Anwser , This Picture
egoroff_w [7]
I think CD because it was positive but also had the fastest velocity in 1 second
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3 years ago
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