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Oliga [24]
4 years ago
10

How would you measure the potential difference across a resistor?

Physics
2 answers:
AleksandrR [38]4 years ago
7 0
The answer to your question is A.
andrew-mc [135]4 years ago
3 0
Right answer of your questions is A
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PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!
Arada [10]

Answer:D

Explanation: both variables change in the same direction. An increase in one variable leads to an increase in the other, a decrease in one lead to a decrease the another

5 0
4 years ago
The velocity of a 10.0 kg object that has 720 J of kinetic energy is m/s. (Report the answer to two significant figures.)
nikdorinn [45]
Kinetic energy<span> is the </span>energy<span> of motion. An object that has motion - whether it is vertical or horizontal motion - has </span>kinetic energy<span>. It is expressed as:

KE = mv^2 /2

720 = 10.0v^2 /2
v = 12 m/s

Hope this answers the question. Have a nice day.</span>
4 0
3 years ago
Read 2 more answers
What defines the mass number of an isotope? A. the sum of the neutrons and protons B. the sum of the neutrons and electrons C. t
Crank

The sum of neutrons and protons defines the mass number of an isotope.

Answer: Option A

<u>Explanation:</u>

Isotopes of an element are defined as an element that possess the same number of protons but different number of neutrons in each atom. Hence the mass number in an isotope depends upon the two sub particles which are number of nucleons (i.e) the number of protons and neutrons. For example: carbon - 12 and carbon - 13 are examples of isotopes, the carbon element with mass number as 12 and 13.

3 0
3 years ago
Can you anser the two questions fast
Rasek [7]

Answer:

yes! what are the questions??

Explanation:

4 0
3 years ago
It is 6.00 km from your home to the physics lab. as part of your physical fitness program, you could run that distance at 10.0 k
kirill115 [55]
<span>1.) It is 6.00km from your home to the physics lab. As part of your physical fitness program, you could run that distance at 10.0km/hr (which uses up energy at the rate of 700W ), or you could walk it leisurely at 3.00km/hr (which uses energy at 290 W). A.)Which choice would burn up more energy? running or walking? b.)How much energy (in joules) would it burn? c.)Why is it that the more intense exercise actually burns up less energy than the less intense one? Follow 2 answers Report Abuse Answers billrussell42 Best Answer: running, at 10 km/hour for 6 km is 6 km / 10 km/hour = 0.6 hour or 36 min energy used is 700 watts or 700 joules/s x 36 min x 60s/min = 1.512e6 joules or 1.5 MJ walking, at 3 km/hour for 6 km 6 km / 3 km/hour = 2 hour or 120 min energy used is 290 watts or 290 joules/s x 120 min x 60s/min = 1.872e6 joules or 1.8 MJ C) should be obvious PS, this has nothing to do with potential energy. billrussell42 · 5 years ago 0 Thumbs up 1 Thumbs down Report Abuse Comment Simon van Dijk I assume the watt consumption is per hour. Then running 6km at 10.0 km/h results in 700*6/10 = 420 w.h and walking in 290*6/3 = 580 w.h So walking would burn up more energy (kwh) b) 1 kilowatt hour = 3 600 000 joules so 420 wh = 0.42 kwh = 1.51.10^6 joule c) when you put more effort in making the distance your energy is used more efficient. Simon van Dijk · 5 years ago 0 Thumbs up 2 Thumbs down Report Abuse Comment</span>
7 0
3 years ago
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