Answer:
Option c) mass
Explanation:
With the increase in energy in energy of an object there will be an increase in its mass.
Also from Einstein's mass-energy equivalence,
where
m = mass of the object
c = speed of the object (usually speed of light or close to it)
which states that energy and mass are inter convertible.
From which it can be concluded that if an object acquires additional energy, it also acquires additional mass.
Answer:
400 J
Explanation:
Given:
Δy = 4.00 m
v₀ = 0 m/s
a = 5.00 m/s²
Find: v²
v² = v₀² + 2aΔy
v² = (0 m/s)² + 2 (5.00 m/s²) (4.00 m)
v² = 40.0 m²/s²
Find KE:
KE = ½ mv²
KE = ½ (20.0 kg) (40.0 m²/s²)
KE = 400 J
Answer:
Work done = 4 J
Final Kinetic Energy = 4 J
Explanation:
From the question,
Work done = force × distance
W = F×d................... Equation 1
Given: F = 4.0 N, d = 1.0 meter.
Substitute these values into equation 1
W = 4×1
W = 4 Joules.
Also,
Kenetic Energy = 1/2 × mass × velocity×velocity.
K.E = 1/2(mv²)........... (2).
But,
F = ma
Where F = 4 N, m = 1 kg.
a = 4/1 = 4 m/s².
Using,
v² = u² + 2as............. Equation 3
Where u = 0 m/s, a = 4 m/s², s = 1 m.
Substitute into equation 3
v² = 0² +2×4×1
v² = 8
v = √8 m/s.
Substitutting into equation 2
K.E = 1/2(1)(√8)²
K.E = 1/2(8)
K.E = 4 J.
Hence the work done and the Final Kinetic energy are thesame = 4 J
Answer:
Explanation:
The energy lost by the handle in lowering is equal to the energy gained by the car in raising the height.
As the mass of car is much more as compared to the jack, so the height raised by the car is very small as compared to the handle of jack.
Imagine you are in a swimming pool 30m deep. Assuming you know that water is denser than air, you would know that the 30m of water above you will carry more weight, and press down on your body. Say you were in a swimming pool 60m deep, you would be sandwiched between 30m of water pressing down on you, and the upthrust created by the 30m of water below you.
In a building 30m up, the pressure will be regulated, as you are in a building. The floor will be strong enough to support the weight of the body, and the body will not recoil into itself.
