The answer would be gravity.
Answer:
Vf₂ = 2 Vf₁
It shows that final speed of Joe is twice the final speed of Jim.
Explanation:
First, we analyze the final speed of Jim by using first equation of motion:
Vf₁ = Vi + at
where,
Vf₁ = final speed of Jim
Vi = initial speed of Jim = 0 m/s
a = acceleration of Jim
t = time of acceleration for Jim
Therefore,
Vf₁ = at ---------------- equation (1)
Now, we see the final speed of Joe. For Joe the parameters will become:
Vf = Vf₂
Vi = 0 m/s
a = a
t = 2t
Therefore,
Vf₂ = 2at
using equation (1):
<u>Vf₂ = 2 Vf₁</u>
<u>It shows that final speed of Joe is twice the final speed of Jim.</u>
When you hit a ball it collides with the bat. When you catch a ball it collides with your hand.
Answer:
L=2*10^-10m
Explanation:
we need to evaluate for a minimum energy:
Planck constant= h = 6,62607015 ×10 -34 kg⋅m2⋅s−1
1.5*10^-18J = 10eV
En= n^2h^2 / 8mL^2
for n=1 (minimum energy)
E1= h^2 / 8mL^2
so...
L^2= h^2/(8mE1)
L^2= (6.63*10^-34)^2 / [ 8(9.11*10^-31 )*(1.5*10^-18J )]
L^2= 4.02*10^-20
L= 2*10^-10 m
Answer:
D. The period would decrease by sqrt (2)
Explanation:
The period of a mass-spring system is given by:
where
m is the mass
k is the spring constant of the spring
If the spring constant is doubled,
k' = 2k
So the new period will be
So the correct answer is
D. The period would decrease by sqrt (2)