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stellarik [79]
4 years ago
14

Biker A is cruising at a speed of 10.0 m/s when she passes biker B who is at rest at the origin of the coordinate system. Biker

B immediately accelerates when he is passed, catching up with biker A after 1.00 minute.
(a) Draw graphs of position, velocity, and acceleration of both bikers as a function of time.
(b) What is the acceleration of biker B, assuming that it is constant?
(c) At what distance from the origin do the two bikers meet?
(d) What is the average speed of biker B during the first 30.0 seconds?

Physics
1 answer:
Burka [1]4 years ago
3 0

Answer: attached

Explanation:

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100 POINTS. PLEASE EXPLAIN
Elina [12.6K]

Answer:

(a) 106 kPa

(b) 0.0377 mol

(c) 17.8 cm

Explanation:

(a) There are three forces on the piston.  Atmospheric pressure pushing down, weight pulling down, and pressure of the gas pushing up.

∑F = ma

PA − mg − PₐA = 0

P = (PₐA + mg) / A

P = Pₐ + (mg / A)

P = 101,300 Pa + (40.0 N) / (π (0.05 m²))

P = 106,393 Pa

P = 106 kPa

(b) Use ideal gas law.

PV = nRT

(106,393 Pa) (π (0.05 m²) (0.11 m)) = n (8.314 Pa m³/mol/K) (20 + 273.15) K

n = 0.0377 mol

(c) Use ideal gas law to find the new volume of the gas.

PV = nRT

(106,393 Pa) (π (0.05 m²) h) = (0.0377 mol) (8.314 Pa m³/mol/K) (200 + 273.15) K

h = 0.178 m

h = 17.8 cm

6 0
4 years ago
Read 2 more answers
A gas bottle contains 0.250 mol of gas at 730 mm hg pressure. if the final pressure is 1.15 atm, how many moles of gas were adde
Ludmilka [50]

Answer: 0.049 mol



Explanation:



1) Data:


n₁ = 0.250 mol

p₁ = 730 mmHg

p₂ = 1.15 atm

n₂ - n₁ = ?


2) Assumptions:


i) ideal gas equation: pV = nRT


ii) V and T constants.


3) Solution:


i) Since the temperature and the volume must be assumed constant, you can simplify the ideal gas equation into:


pV = nRT ⇒ p/n = RT/V ⇒ p/n = constant.


ii) Then p₁ / n₁ = p₂ / n₂


⇒ n₂ = p₂ n₁ / p₁


iii) n₂ = 1.15atm × 760 mmHg/atm × 0.250 mol / 730mmHg = 0.299 mol


iv) n₂ - n₁ = 0.299 mol - 0.250 mol = 0.049 mol

7 0
3 years ago
A particle oscillates harmonically x = A cos(ωt + φ0), with amplitude 9 m, angular frequency π s −1, and initial phase π 3 radia
Gekata [30.6K]

Answer:

t = \frac{5}{12} s

Explanation:

As we know that the equation of particle position is given as

x = A cos(\omega t + \phi_0)

Now the speed of the particle is given as

v = A\omega sin(\omega t + \phi_0)

now we know that potential energy and kinetic energy is equal

so we have

\frac{1}{2} mv^2 = \frac{1}{2}kx^2

so we will have

A^2\omega^2 sin^2(\omega t + \phi_0) = A^2\omega^2 cos^2(\omega t + \phi_0)

tan^2(\omega t + \phi_0) = 1

\omega t + \phi_0 = \frac{\pi}{4} or \frac{3\pi}{4}

\pi t = \frac{3\pi}{4} - \frac{\pi}{3}

\pi t = \frac{5\pi}{12}

t = \frac{5}{12} s

6 0
3 years ago
What was the hiker's average velocity during Part A of the hike?
jarptica [38.1K]
Answer is C. 4km/h east
8 0
3 years ago
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A resistance is added in parallel to a 470 Ω resistance to give an effective resistance of 330 Ω. What is the approximate value
saw5 [17]
I think its c on the test I had
4 0
4 years ago
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