Biker A is cruising at a speed of 10.0 m/s when she passes biker B who is at rest at the origin of the coordinate system. Biker
B immediately accelerates when he is passed, catching up with biker A after 1.00 minute.
(a) Draw graphs of position, velocity, and acceleration of both bikers as a function of time.
(b) What is the acceleration of biker B, assuming that it is constant?
(c) At what distance from the origin do the two bikers meet?
(d) What is the average speed of biker B during the first 30.0 seconds?
(a) Draw graphs of position, velocity, and acceleration of both bikers as a function of time.
(b) What is the acceleration of biker B, assuming that it is constant?
(c) At what distance from the origin do the two bikers meet?
(d) What is the average speed of biker B during the first 30.0 seconds?
1 answer:
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Answer:
a)
b)
Step-by-step explanation.
In order to solve this problem, we mus start by plotting the given points and charges. That will help us visualize the problem better and determine the direction of the forces (see attached picture).
Once we drew the points, we can start calculating the forces:
which yields:
(I will assume the positions are in meters)
Next, we can make use of the force formula:
so we substitute the values:
which yields:
Now we can find its components:
And we can now write them together for the first force, so we get:
We continue with the next force. The procedure is the same so we get:
which yields:
Next, we can make use of the force formula:
which yields:
Now we can find its components:
And we can now write them together for the second, so we get:
We continue with the next force. The procedure is the same so we get:
which yields:
Next, we can make use of the force formula:
which yields:
Now we can find its components:
And we can now write them together for the third force, so we get:
So in order to find the resultant force, we need to add the forces together:
so we get:
So when adding the problem together we get that:
which is the answer to part a), now let's take a look at part b).
b)
Basically, we need to find the magnitude of the force and divide it into the test charge, so we get:
which yields:
and now we take the formula for the electric field which is:
so we go ahead and substitute:
