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3 years ago

J+j-60=80 solve for j

Mathematics

1 answer:

JulsSmile [24]3 years ago

5 0

Answer:

j=70

im sure of it

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2 / 5 + ? / 15 = 16 / 15

maksim [4K]

Answer:

Step-by-step explanation:

I dont know the answer hope this helps

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3 years ago

Plz help ASAP I need to find the slope of the line

dmitriy555 [2]

Use formula y2-y1 over x2 - x1

3-0/4-0

3/4 is ur answer

3 0

4 years ago

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Someone please help me! I would appreciate it so much!

Alexxandr [17]

5.1 • 0.79 = 4.029
the apples cost $4.03

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4 years ago

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Determine the volume of the figure. Use 3.14 for π. Round your answer to the nearest tenth. Show all of your work.

Ostrovityanka [42]

Answer:

1985 cubic units (written as un. with the cubed exponent)

Step-by-step explanation:

First, you find the volume of the cylinder

Here's the formula:

$V=\pi r^{2}h\\V=volume\\r=radius\\h=height$

Now, you plug in and solve.

$V=(3.14)(7.2^{2})(7.4)\\V=(3.14)(51.84)(7.4)\\V=(162.7776)(7.4)\\V=1204.55424\\rounded:\\V=1204.6$

Then, you find the volume of the dome.

Here's the formula:

$volume/of/a/sphere=\frac{4}{3}\pi r^{3}\\volume/of/a/dome:\\V=\frac{2}{3}\pi r^{3} \\V=volume\\r=radius$

Now, you just plug in and solve.

$V=(\frac{2}{3})(\pi)(r^{3})\\V=(\frac{2}{3})(3.14)(7.2^{3})\\V=(\frac{2}{3})(3.14)(373.248)\\V=(2.093)(373.248)\\V=781.208064\\rounded:\\V=781.2$

Finally, you add them together, and there's your answer!

$1204.6+781.2=1985.8$

Hope this helped!

<em>brainliest?</em>

8 0

3 years ago

Find, correct to four decimal places, the length of the curve of intersection of the cylinder 16x2 + y2 = 16 and the plane x + y

Yuri [45]

Let the curve C be the intersection of the cylinder

$16x^2+y^2=16$

and the plane

$x+y+z=1$

The projection of C on to the x-y plane is the ellipse

$16x^2+y^2=16$

To see clearly that this is an ellipse, le us divide through by 16, to get

$\frac{x^2}{1}+ \frac{y^2}{16}=1$

$\frac{x^2}{1^2}+ \frac{y^2}{4^2}=1$ ,

We can write the following parametric equations,

$x=cos(t), y=4sin(t)$

for

$0\le t \le 2\pi$

Since C lies on the plane,

$x+y+z=1$

it must satisfy its equation.

Let us make z the subject first,

$z=1-x-y$

This implies that,

$z=1-sin(t)-4cos(t)$

We can now write the vector equation of C, to obtain,

$r(t)=(cos(t),4sin(t),1-cos(t)-4sin(t))$

The length of the curve of the intersection of the cylinder and the plane is now given by,

$\int\limits^{2\pi}_0 {|r'(t)|} \, dt$

But

$r'(t)=(-sin(t),4cos(t),sin(t)-4cos(t))$

$|r'(t)|=\sqrt{(-sin(t))^2+(4cos(t))^2+(sin(t)-4cos(t))}$

$\int\limits^{2\pi}_0 {\sqrt{2sin^2(t)+32cos(t)-8sin(t)cos(t)} }\, dt=24.08778184$

Therefore the length of the curve of the intersection intersection of the cylinder and the plane is 24.0878 units correct to four decimal places.

6 0

4 years ago