13/15
Common denominator is 15, 1 3/15 minus 5/15 equals 13/15
Answer:
B. 264
Step-by-step explanation:
Although the figure may look odd, This is just a square pyramid on it's side.
So, to find the surface area, we need to find the area of the base and the area of the faces and add them together.
To find the area of the base:
Since the base is a square, all we have to do is multiply 8 by itself.
8 * 8 = 64
The area of the base is 12.5 in^2
To find the area of the faces:
Since the faces are triangles, we have to multiply the length by the height and divide by 2.
8 * 12.5 = 100
100/2 = 50
The area of one face is 50 in^2
To find the surface area:
Add the area of the base to the area of all 4 sides.
64 + 4(50)
64 + 200 = 264
The surface area of the pyramid is B. 264 in.^2
The equation of the line through (0, 1) and (<em>c</em>, 0) is
<em>y</em> - 0 = (0 - 1)/(<em>c</em> - 0) (<em>x</em> - <em>c</em>) ==> <em>y</em> = 1 - <em>x</em>/<em>c</em>
Let <em>L</em> denote the given lamina,
<em>L</em> = {(<em>x</em>, <em>y</em>) : 0 ≤ <em>x</em> ≤ <em>c</em> and 0 ≤ <em>y</em> ≤ 1 - <em>x</em>/<em>c</em>}
Then the center of mass of <em>L</em> is the point 
with coordinates given by
where 
is the first moment of <em>L</em> about the <em>x</em>-axis, 
is the first moment about the <em>y</em>-axis, and <em>m</em> is the mass of <em>L</em>. We only care about the <em>y</em>-coordinate, of course.
Let <em>ρ</em> be the mass density of <em>L</em>. Then <em>L</em> has a mass of
Now we compute the first moment about the <em>y</em>-axis:
Then
but this clearly isn't independent of <em>c</em> ...
Maybe the <em>x</em>-coordinate was intended? Because we would have had
and we get
Answer:
i have no idea girl or boy
Step-by-step explanation:
140%
Step-by-step explanation:
