A number is chosen at random from 1 to 50 find the probability of selecting composite numbers

LUCKY_DIMON [66]

175% of 14.2 is saying that

1.75(14.2)=24.9

Any questions please just ask. Thank you.

7 0

3 years ago

Show that in any group of 101 people there are at least two persons having the same number friends (It is assumed that if a pers

vladimir1956 [14]

Answer:

Step-by-step explanation:

Let us assume that if possible in the group of 101, each had a different number of friends. Then the no of friends 101 persons have 0,1,2,....100 only since number of friends are integers and non negative.

Say P has 100 friends then P has all other persons as friends. In this case, there cannot be any one who has 0 friend. So a contradiction. Hence proved

Part ii: EVen if instead of 101, say n people are there same proof follows as

if different number of friends then they would be 0,1,2...n-1

If one person has n-1 friends then there cannot be any one who does not have any friend.

Thus same proof follows.

7 0

3 years ago

A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).

maksim [4K]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}$

$\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}$

3 0

2 years ago

PLEASE HELP ASAP!!!!!

irakobra [83]

Answer:

D

Step-by-step explanation:

7 0

4 years ago

Read 2 more answers

Two numbers have a sum of 18, and 4 times the first number minus the second number is equal to 17. What is the smallest number?

sammy [17]

Answer:

The smallest number is 7

Step-by-step explanation:

Using simultaneous equation;

x+y = 18.....(1)

4x-y = 17.....(2)

from equation (1)..

x+y = 18

y = 18-x...(3)

substitute y into equation (2)

4x-y = 17

4x-(18-x) = 17

4x-18+x = 17

4x+x = 17+18

5x = 35

x = 35÷5

x = 7

substitute x into equation (3)

y = 18-x

y = 18-7

y = 11

Therefore; x=7

y=11

11+7=18

(4×7)-11=17

the smallest number is 7

4 0

3 years ago