First one m = .0666666
second one i don't know
third one is .1
Answer:
(56/45)x^7
Step-by-step explanation:
28x^4 20
---------- ÷ ----------- becomes
27 24x^3
28x^4 24x^3
---------- * ----------- if we invert the divisor fraction and then multiply.
27 20
We get: (28)(24)
-------------- x^7
(27)(20)
which reduces to (7)(24) x^7 (7)(8)x^7
--------------- = ------------- = (56/45)x^7
27(5) 9(5)
Complete question is;
An advertising banner has four sections, as modeled in the attached image. Two sections are congruent trapezoids, and two sections are congruent right triangles. Which measurement is the best estimate of the area of the banner in square meters?
Answer:
6 m²
Step-by-step explanation:
Since we are told that there are two congruent trapezoid, it means that they will have same base of 1m.
This Means the total base of the entire triangle will be;
Base = 1 + 1¾ + 1 + 1¾ = 5.5 m
Height of main triangle = 2 m
Thus,
Area = ½ × 5.5 × 2 = 5.5 m²
We are looking for best estimate, so let's approximate to the nearest whole number to get 6 m²
168 yds i’m pretty sure sorry if i’m wrong
Answer:
SinL = 7/25
CosL = 24/25
TanL = 7/24
Step-by-step explanation:
Find the diagram attached.
Using SOH CAH TOA in trigonometry identity to find the sinL, cosL and TanL
Note that the hypotenuse is the longest side = 25
The opposite will be the side facing the acute angle L
Opposite = 7
Adjacent = 24
For SinL
sinL = Opposite/Hypotenuse {SOH}
SinL = 7/25
For cosL:
CosL = Adjacent/Hypotenuse{CAH}
CosL = 24/25
For tanL:
TanL = Opposite/Adjacent {TOA}
TanL = 7/24