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valentina_108 [34]
3 years ago
5

Can someone pls help I can do this

Mathematics
1 answer:
GrogVix [38]3 years ago
4 0

Answer:

these are supplementary

and x = 50

Step-by-step explanation:

one straight line = 180 degrees

there are only two angles making up this 180 degree line, so by definition they are supplementary

76 + 2x + 4 = 180

80 + 2x = 180

2x = 100

x = 50

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Pls really need help asapppp
Anit [1.1K]

Answer:

105 sq cm

Step-by-step explanation:

The bottom rectangle is 6 x 15 = 90 sq cm

The triangle at the top has a length of 15 - 9 = 6 cm and a height of 11 - 6 = 5 cm.

A triangle is 1/2bh so 1/2 x 6 x 5 = 15 sq cm

Add the areas together

8 0
2 years ago
6 = -5 -x solve for x
makkiz [27]

Answer:

<h2>x = -11</h2>

Step-by-step explanation:

In algebra, the goal is always to isolate the variable, so that its value can be determined.

<h3>Step 1: Add x</h3>

6 + x = -5

<h3>Step 2: Subtract 6</h3>

x = -11

<h3>Step 3: Check</h3>

6 = -5 - -11

6 = -5 + 11

6 = 6 ✔

<h3>Step 4: Answer</h3>

x = -11

I'm always happy to help :)

7 0
3 years ago
What is the approximate area of the circle, in square centimeters? Use 3.14 for π (pi). Record your answer on the grid. then fil
iragen [17]
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This mapping shows a functional relationship.
Dmitriy789 [7]

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Step-by-step explanation:

3 0
3 years ago
A worker at a landscape design center uses a machine to fill bags with potting soil. Assume that the quantity put in each bag fo
defon

Answer:

a) The expected value is given by:

E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11

The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

And the standard deviation is just the square root of the variance and we got:

Sd(x) = \sqrt{0.3333}= 0.5774

b) P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}, a \leq x \leq b

And using this function we got:

P(X

c) P(X>10.5)

And using the complement rule and the cumulative distribution function we got:

P(X>10.5)= 1-P(X

Step-by-step explanation:

For this case we define the random variable X=quantity put in each bag , and we know that the distribution for X is given by:

X \sim Unif (a= 10, b =12)

Part a

The expected value is given by:

E(X) =\frac{a+b}{2}= \frac{10+12}{2}= 11

The variance is given by:

Var(X) = \frac{(b-a)^2}{12}= \frac{(12-10)^2}{12}= 0.3333

And the standard deviation is just the square root of the variance and we got:

Sd(x) = \sqrt{0.3333}= 0.5774

Part b

For this case we want this probability:

P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a}, a \leq x \leq b

And using this function we got:

P(X

Part c

For this case we want this probability:

P(X>10.5)

And using the complement rule and the cumulative distribution function we got:

P(X>10.5)= 1-P(X

3 0
3 years ago
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