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vichka [17]
3 years ago
10

Which element would you expect to be more reactive: phosphorus (P) or fluorine (F)

Chemistry
2 answers:
goblinko [34]3 years ago
6 0

Answer:

(F)

Explanation:

Studentka2010 [4]3 years ago
4 0

Answer:

Fluorine

Explanation:

Fluorine is the most electronegative element because it has 5 electrons in it's 2P shell.

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What will most likely happen when a warmer air mass exists above a polar ice sheet?
Andre45 [30]
I believe it is "The temperature of the ice sheet will be lowered" because it will most likely lower just a bit due to the heat. It's not going to fully melt but it will lower just a bit.
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8 0
3 years ago
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A a black metal measures 2 cm x 3 cm x 2.5 cm if it's much is 67.5 grams calculate its density​
liraira [26]

Answer:

d=4.5  g/cm³

Explanation:

v=l x w x h

v=2 x 3 x 2.5

v=15 cm³

d=m/v

d=67.5/15

d=4.5  g/cm³

3 0
3 years ago
A chemistry teacher has a 560-cm length of magnesium ribbon. For a class experiment, each student requires an 8.5-cm length of t
Ugo [173]
N=560/8.5=65.88

65 students
3 0
3 years ago
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Determine the change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizi
uysha [10]

Answer: The change in boiling point for 397.7 g of carbon disulfide (Kb = 2.34°C kg/mol) if 35.0 g of a nonvolatile, nonionizing compound is dissolved in it is 2.9^0C

Explanation:

Elevation in boiling point:

T_b-T^o_b=i\times k_b\times \frac{w_2\times 1000}{M_2\times w_1}

where,

T_b = boiling point of solution = ?

T^o_b = boiling point of pure carbon disulfide= 46.2^oC

k_b = boiling point constant  =2.34^0Ckg/mol

m = molality

i = Van't Hoff factor = 1 (for non-electrolyte)

w_2 = mass of solute = 35.0 g

w_1 = mass of solvent (carbon disulphide) = 397.7 g

M_2 = molar mass of solute = 70.0 g/mol

Now put all the given values in the above formula, we get:

(T_b-46.2)^oC=1\times (2.34^oC/m)\times \frac{(35.0g)\times 1000}{70.0\times (397.7g)}

T_b=49.1^0C

Therefore, the change in boiling point is (49.1-46.2)^oC=2.9^0C

5 0
4 years ago
How many atoms are there in 8.08 moles of carbon dioxide
sertanlavr [38]

Answer:

145.97×10²³ atoms

Explanation:

Given data:

Number of moles of CO₂ = 8.08 mol

Number of atoms of CO₂ = ?

Solution:

1 mole of CO₂ contain 1 mole C atom.

8.08 mole contain 8.08× 1 = 8.08 mole of C atom.

1 mole of CO₂ contain 2 moles of O atom.

8.08mole contain 8.08×2 = 16.16 mole of O atom.

Total number of moles of atoms = 8.08 mole + 16.16 mole

Total number of moles of atoms = 24.24 mol

Number of atoms of CO₂:

1 mole of any substance contain 6.022×10²³ atoms.

24.24 mol ×6.022×10²³ atoms / 1 mol

145.97×10²³ atoms

7 0
3 years ago
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