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DaniilM [7]
3 years ago
10

Predict the geometry about each interior atom in acetic acid:

Chemistry
1 answer:
aleksandr82 [10.1K]3 years ago
5 0

The atomic structure of the acetic acid is:

                        H     O

                        l       l

                H – C – C – O – H

                        l

                        H

 

We can see from the structure that there are 2 interior atoms, and these are all Carbon atoms.


The geometry is:

Tetrahedral on First Carbon

Trigonal Planar on Second Carbon

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How many nitrogen atoms are in 4AgNO3
tensa zangetsu [6.8K]

Answer:

Silver/AG= 4

Nitrogen/N=4

Oxygen/O=12

Explanation:

6 0
2 years ago
What is the molarity of solution prepared by dissolving 11.75 g of KNO3 in enough water to produce 2.00 L of solution?
zysi [14]
The molar mass of the compound potassium nitrate, KNO3 is equal to 101.1032 g/mol. Then, we determine the number of moles present in the given amount,
                       n = 11.75g / (101.1032 g/mol) = 0.116 mol
Then, molarity is calculated by dividing the number of moles by the volume of the solution. The answer is therefore 0.058 M. 
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3 years ago
Sheela wants to make a computer model of a land ecosystem. Part of her model simulates the chemical processes of photosynthesis
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3 years ago
Read 2 more answers
Determine ΔH for the reaction CaCO3 → CaO + CO2 given these data: 2 Ca + 2 C + 3 O2 → 2 CaCO3 ΔH = −2,414 kJ C + O2 → CO2 ΔH = −
kicyunya [14]

Answer:

The ΔH for the reaction is -456.5 KJ

Explanation:

Here we want to determine ΔH for the reaction;

Mathematically;

ΔH = ΔH(product) - ΔH(reactant)

In the case of the first reaction;

ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3)  ...........................(*)

From the other reactions, we can get the respective ΔH for the individual molecule in the reaction

In second reaction;

Kindly note that for elements, molecule of gases, ΔH = 0

What this means is that throughout the solution;

ΔH(Ca)  = 0 KJ

ΔH(O2) = 0 KJ

ΔH(C) = 0 KJ

Thus, in writing the equation for the subsequent chemical reactions, we shall need to write and equate the overall ΔH for the reaction to that of the product alone

So in the second reaction

ΔH = 2ΔH(CaCO3)

Thus;

-2414/2 = ΔH(CaCO3)

ΔH(CaCO3) = -1,207  KJ

Moving to the third reaction, we have;

ΔH = ΔH(CO2)

Hence ΔH(CO2) = -393.5 KJ

For the last reaction;

ΔH = ΔH(CaO)

Hence ΔH(CaO) = -1270 KJ

Going back to equation *

ΔH = ΔH(CaO) + ΔH(CO2) - ΔH(CaCO3)

Using the values of the ΔH  of the respective molecules given above,

ΔH  = -1270 + (-393.5) - (-1207)

ΔH  = -456.5 KJ

8 0
3 years ago
Increasing order of unsaturation
Basile [38]

Whats the question? Im not sure what your asking

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