Mass is the amount of matter in the object, and is not affected by gravity. Weight, on the other hand, is directly related to gravity and how much you pull to the ground.

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3 years ago

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The standard entropy of liquid methanol at 298K is 126.8 J/K-mol and its heat capacity is 81.6 J/K-mol. Methanol boils at 337K w

USPshnik [31]

Explanation:

First, we will calculate the entropies as follow.

$\Delta S_{2} = C_{p_{2}} ln \frac{T_{2}}{T_{1}}$ J/K mol

As, $T_{1}$ = 298 K, $T_{2}$ = 373.8 K

Putting the given values into the above formula we get,

$\Delta S_{2} = C_{p_{2}} ln \frac{T_{2}}{T_{1}}$ J/K mol

= $81.6 ln (\frac{373.8}{298})$

= 18.5 J/K mol

Now,

$\Delta S_{3} = \frac{\Delta H_{vap}}{T_{b.p}}$

= $\frac{35270 J}{373.8}$

= 94.2 J/mol K

Also,

$\Delta S_{4} = C_{p_{4}} ln \frac{T_{2}}{T_{1}}$

= $43.89 \times ln (\frac{800}{373.8})$

= 33.4 J/K mol

Now, we will calculate the entropy of one mole of methanol vapor at 800 K as follows.

$\Delta S_{T} = \Delta S^{o}_{1} + \Delta S_{2} + \Delta S_{3} + \Delta S_{4}$

= (126.8 + 18.5 + 94.2 + 33.4) J/K mol

= 272.9 J/K mol

Thus, we can conclude that the entropy of one mole of methanol vapor at 800 K is 272.9 J/K mol.

7 0

3 years ago

KClO3  ____ KCl + ____ O2 reaction type

Leona [35]

Decomposition because one compound into two

8 0

3 years ago