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Aleksandr [31]
4 years ago
9

Why is Cellular Respiration so important?

Chemistry
1 answer:
Nesterboy [21]4 years ago
5 0
I say it’s A. Hopefully
You might be interested in
The middle block of the periodic table is called?​
Masteriza [31]

Answer: The transition metals make up the middle block of he periodic table

3 0
3 years ago
G the hydrogen generated in this lab was a product of the reaction between magnesium and hydrochloric acid. which of these react
Colt1911 [192]

The limiting reactant is determined by the supply and stoichiometric equation.

<h3>Limiting reactants</h3>

They are reactants that are limited in availability, and thus, determine how far reactions can go in terms of producing products.

In a reaction involving magnesium and hydrochloric acid to produce hydrogen gas as follows:

Mg + 2HCl --- > MgCl_2 + H_2

The number of moles of HCl is twice that of Mg. Thus, if both reactants are supplied in the required proportion, no reactant will be limiting.

However, if the number of moles of HCl supplied is not up to twice that of Mg, HCl will become limiting. Also, if the amount of Mg supplied is not equal to half of that of HCl supplied, Mg will be limiting.

More on limiting reactants can be found here: brainly.com/question/14225536

#SPJ1

3 0
2 years ago
Calculate the solubility of CaF2 in g/L (Ksp = 4.0 x 10-8). 2. What is the pH of a solution containing a hydrogen ion concentrat
Pepsi [2]

Answer:

\large \boxed{1. \text{ 0.17 g/L; 2. 3.52; 3. Cl; 4. (a) +3; (b) +4; (c) +6}}

Explanation:

1. Solubility of CaF_2

(a) Molar solubility

CaF₂ ⇌ Ca²⁺ + 2F⁻

K_{\text{sp }} = \text{[Ca$^{2+}$]}\text{[F$^{-}$]}^{2}= 4.0 \times 10^{-8}\\s(2s)^{2}=4.0 \times 10^{-8}\\4s^{3} = 4.0 \times 10^{-8}\\s^{3} = 1.0 \times 10^{-8}\\s =2.2 \times 10^{-3}\text{ mol/L}

(b) Mass solubility

\text{Solubility} = 2.2 \times 10^{-3} \text{ mol/L} \times \dfrac{\text{78.07 g}}{\text{1 L }} = \text{0.17 g/L}\\\\\text{The solubility of CaF$_{2}$ is $\large \boxed{\textbf{0.17 g/L}}$}

2. pH

pH = -log [H⁺] = -log(3.0 × 10⁻⁴) = 3.52

3. Oxidizing and reducing agents

Zn + Cl₂ ⟶ ZnCl₂

\rm \stackrel{\hbox{0}}{\hbox{Zn}} + \stackrel{\hbox{0}}{\hbox{ Cl}_{2} }\longrightarrow \stackrel{\hbox{+2}}{\hbox{Zn}}\stackrel{\hbox{-1}}{\hbox{Cl}_{2}}

The oxidation number of Cl has decreased from 0 to -1.

Cl has been reduced, so Cl is the oxidizing agent.

4. Oxidation numbers

(a) Al₂O₃

\stackrel{\hbox{$\mathbf{+3}$}}{\hbox{Al}_{2}}\stackrel{\hbox{-2}}{\hbox{O}_{3}}

1O = -2; 3O = -6; 2Al  = +6; 1Al = +3

(b) XeF₄

\stackrel{\hbox{$\mathbf{+4}$}}{\hbox{Xe}}\stackrel{\hbox{-1}}{\hbox{F}_{4}}

1F = -1; 4F = -4; 1 Xe = +4

(c) K₂Cr₂O₇

\stackrel{\hbox{${+1}$}}{\hbox{K}_{2}}\stackrel{\hbox{$\mathbf{+6}$}}{\hbox{Cr}_{2}}\stackrel{\hbox{-2}}{\hbox{O}_{7}}

1K = +1; 2K = +2; 1O = -2; 7O = -14

+2 - 14 = -12

2Cr = + 12; 1 Cr = +6

8 0
4 years ago
235
lisov135 [29]

Answer:

Average atomic mass of uranium = 237.97 amu

Explanation:

Given data:

Abundance of U-234 = 0.01%

Abundance of U-235 = 0.71%

Abundance of U-238 = 99.28%

Average atomic mass of uranium = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass)  / 100

Average atomic mass  = (234×0.01)+(235×0.71)+(238+99.28) /100

Average atomic mass =  2.34 + 166.85+23628.64 / 100

Average atomic mass = 23797.83 / 100

Average atomic mass = 237.97 amu.

3 0
3 years ago
Is cyclopentane an isomer of pentane? Explain.
Georgia [21]
Cyclopentane is NOT an isomer of pentane.

Isomers must have the same molecular formula.

The molecular formula of pentane is C₅H₁₂, while the molecular formula of cyclopentane is C₅H₁₀.

The two molecules cannot be isomers.
8 0
4 years ago
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