Answer: Okay, the answer is x^2/68+(y+3)^2/17=1.
Step-by-step explanation: Step. 1 Complete the square for 4y^2+24y: 4(y+3)^2−36.
Step 2. You’ll need to substitute 4(y+3)^2−36 for 4y^2+24y in the equation x^2+4y^2+24y=32: x^2+4(y+3)^2–36=32.
Step 3. So you’ll need to move –36 to the right side of the equation by adding 36 to the both sides: x^2+4(y+3)^2=32+36.
Step 4 You add 32 and 36: x^2+4(y+3)^2=68.
Step 5. You divide each term by 68 to make the right side equal to one: x^2/68+4(y+3)^2/68=68/68.
And step 6. You’ll need to simplify each term in the equation in order to set the right side equal to 1. The standard form of an ellipse or hyperbola requires the right side of the equation be 1: x^2/68+(y+3)^2/17=1. I hope you download Math-way app to calculate this ellipse in standard form to be extremely helpful, please mark me as brainliest, and have a great weekend! :D
Hey You!
132*42% = 55.44
132 - 55.44 = 76.56
So, the Millers paid $55.44 for gas and $76.56 for electricity.
{(-1,3), (4,2), (-1,5)}
The same inputs should have the same output, but different inputs are allowed to have the same output.
I hope this helped!
As consecutive odd numbers differ by two (example: 3, 5, 7), the first odd number can be expressed as 2n + 1, the next can be found by adding two to the first to get 2n + 1 + 2 which simplifies to 2n + 3. Finally the expression for the third consecutive odd integer can be found by adding two to the previous, 2n + 3, to get 2n + 5. Adding these three together and setting them equal to your sum gets the equation
2n + 1 + 2n + 3 + 2n + 5 = 63
Combine like terms and solve For n.
Once you have n, you must substitute it back into your three expressions (2n + 1, 2n + 3, 2n + 5) to find the three odd integers.
Hope this helps :)
2x^3 + 9x - 8 - (4x^2 - 15x + 7)....distribute thru the parenthesis
2x^3 + 9x - 8 - 4x^2 + 15x - 7....combine like terms
2x^3 - 4x^2 + 24x - 15 <==
