Answer:
c
Explanation:
Hello!
To solve this problem we need to know the velocity and position of the train as a fucntion of time and acceleration. Since the train started from rest, these are the formulas:
v = at
x = (1/2)a*t^2
From the first equation we can know the time as a division between the velocity and the acceleration:
t = (v/a)
Replacing this value in the second equation we get:
x = (1/2)*a*(v/a)^2 = v^2/(2*a)
Solving for a:
a = (1/2)*(v^2/x)
Now, we know that when x=5.6km =5600 m, the velocity of the train is v =42 m/s
Therefore:
a = (1/2)*(42^2/5600) m/s^2 = 0.1575 m/s^2
So, the answer is c, the acceleration of the train during the first 5.6 km is colse to 0.16m/S^2
Answer:
i think number 4 :/ i hope its right...
Answer:
Galileo called the dark spots on the sun sunspots.
Answer:
In physics, power is the amount of energy transferred or converted per unit time. In the ... Power (physics) ... Angular acceleration / displacement / frequency / velocity. show. Scientists ... Hence the formula is valid for any general situation. ... because they define the maximum performance of a device in terms of velocity ratios
Explanation: