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4 years ago

What happens when a muscle contracts

1 answer:

8 0

Well, your muscles are made of of the two (most important) filaments. When one of them moves over the other filaments, the muscles is contracted. If there is an answer choice, I may be able to provide you with a more accurate answer, if this did not already help. ;)

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Help please, I don't get it

Sergio [31]

Answers:

a) $\hat F=(0.83,-0.55) N$

b) $\hat D=(-0.44,-0.89) m$

c) $\hat V=(-0.47,0.88) m/s$

Explanation:

A unit vector is a vector whose magnitude (length) is equal to 1. This kind of vector is identified as $\hat v$ and the way to calculate is as follows:

$\hat v=\frac{\vec v}{|v|}$

Where:

$\vec v=(x,y)$ is the vector

$|v|=\sqrt{x^{2}+y^{2}}$ is the magnitude of the vector

Having this information clarified, let's begin with the answers:

a) Force Vector

$\vec F=(9.0 \hat i - 6.0 \hat j) N$

Magnitude of $\vec F$ :

$|F|=\sqrt{(9.0 \hat i)^{2}+(-6.0 \hat j)^{2 }}N=10.81 N$

Unit vector:

$\hat F=\frac{\vec F}{|F|}$

$\hat F=\frac{(9.0 \hat i - 6.0 \hat j) N}{10.81 N}$

$\hat F=\frac{9.0}{10.81} N-\frac{6.0}{10.81}N$

$\hat F=(0.83,-0.55) N$

b) Displacement Vector

$\vec D=(-4.0 \hat i - 8.0 \hat j) m$

Magnitude of $\vec D$ :

$|D|=\sqrt{(-4.0 \hat i)^{2}+(-8.0 \hat j)^{2 }}m=8.94 m$

Unit vector:

$\hat D=\frac{\vec D}{|D|}$

$\hat D=\frac{(-4.0 \hat i - 8.0 \hat j) m}{8.94 m}$

$\hat D=\frac{-4.0}{8.94} Nm+\frac{-8.0}{8.94}m$

$\hat D=(-0.44,-0.89) m$

c) Velocity Vector

$\vec V=(-3.50 \hat i + 6.50 \hat j) m/s$

Magnitude of $\vec V$ :

$|V|=\sqrt{(-3.50 \hat i)^{2}+(6.50 \hat j)^{2}}m/s=7.38 m/s$

Unit vector:

$\hat V=\frac{\vec V}{|V|}$

$\hat V=\frac{(-3.50 \hat i +6.50 \hat j) m/s}{7.38 m/s}$

$\hat V=\frac{-3.50}{7.38} m/s+\frac{6.50}{7.38}m/s$

$\hat V=(-0.47,0.88) m/s$

8 0

4 years ago

An actor who memorizes his lines word-for-word has demonstrated _____ learning.

Nana76 [90]

Mechanical association learning used by an actor to memorize his lines

8 0

3 years ago

Read 2 more answers

A single conservative force F(x) = b x + a acts on a 4.37 kg particle, where x is in meters, b = 6.09 N/m and a = 5.96 N. As the

Alenkasestr [34]

Answer:104.41 J

Explanation:

Given

Force acting $F(x)=bx+a$

mass of particle $m=4.37 kg$

$a=5.96 N$

$b=6.09 N/m$

Work done is given by

$W=\int_{a}^{b}F.dx$

$W=\int_{0.652}^{5.1}\left ( 6.09x+5.96\right )dx$

$W=\left [ 6.09\times \left ( \frac{x^2}{2}\right )+5.96\times x\right ]_{0.652}^{5.1}$

$W=77.906+26.51 J$

$W=104.41 J$

4 0

4 years ago

A metal sphere, X, has an initial net charge of −6 × 10−6 coulomb and an identical sphere, Y, has an initial net charge of +2 ×

STatiana [176]

When the two spheres touch each other, part of the charge recombine together. The part of charge that recombines is the excess of positive charge on sphere Y, $Q_y = +2 \cdot 10^{-6}C$ , that recombines with an equivalent charge of $-2 \cdot 10^{-6}C$ located on sphere X. As a result, the total charge remained on the two spheres is the excess of negative charge remained on sphere X:
$Q=-4 \cdot 10^{-6}C$
Since the two spheres are identical, they have same capacity, so this charge will now redistribute equally on the two spheres: therefore, at the end, each sphere will have
$\frac{Q}{2}=-2 \cdot 10^{-6} C$

8 0

3 years ago

When electrons are moving freely between many positive ions, what type of bond is occuring?

exis [7]

Answer:

a metallic

Explanation:

Metal atoms are joined together by metallic bonds. Metals can form cations (positive ions) with a sea of delocalized electrons.

8 0

3 years ago