The answer to this is 1 kg.
You use this equation:
m2 = m1 (g - a) / [a + g u cos θ + g sin θ]
You plug in the given values:
m2 = 0.7 (9.81 - 0.2) / [0.2 + 9.81(0.20) cos 30 + 9.81 sin 30)
The result is
m2 = 1 kg
The correct answer is<span> The earth casts a shadow on the moon
The Earth casts a shadow on the moon and that's why we can't see the remaining parts. The parts that we can see are what we call the lunar phases.</span>
Answer:
Let’s assume that the projectile has the same initial velocity in both cases. It is necessary to find that velocity.
u = u[x]i +u[y]j = [u cos 15]i + [u sin 15]j
The p.v. ; s = s[x]i +s[y]j , get the time of flight by letting s[y]=0
s[y] = [u(y)].t -[1/2]gt^2 =0 , so t = 2u[y]/g
t = [ 2 u sin 15]/g eq 1
s[x] = [ u cos 15] .t eq 2 , substitute in eq q into eq2
range =r = [ u cos 15 ][ 2u sin 15 ]/g =[u^2/g][ 2 sin 15 . cos 15],
r =[ u^2 sin 30]/g =1.5 km
( from this we see that ,in general, r = [u^2 .sin (2a)]/g
u^2 = [ 3g] , eq 1
Now do the 2 nd part
r[2] = [u^2 sin (2a)]/g , eq 2 Let a =45 and substitute eq 1 into eq 2
r[2] = [3g sin 90]/g
r[2] =3 km.
Explanation:
Answer:
Los datos que tienes son:
m = 13 kg
d = 46 m
∪ = 0,45
g = 9,8 m/s²
Fr = ?
w = ?
Lo primero que haremos que calcular Fr
Fr = ∪mg
Fr = (0,45) (13 kg) (9,8 m/s²)
Fr = 57,33 N
Calculamos el trabajo realizado.
w = Fd
w = (57,33 N) (46 m)
w = 2637,18 Joules
Respuesta.
El trabajo realizado es 2637,18 Joules
Explanation:
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