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PtichkaEL [24]
3 years ago
5

a 4.0 kg ball is attached to 0.70 m string and spun at 2.0 m/s. what is the centripetal acceleration ?

Physics
2 answers:
konstantin123 [22]3 years ago
4 0
A(cp) = v^2/R

a(cp) = (2.0)^2/0.70

a(cp) = 4.00/0.70

a(cp) = 5.7 m/s^2 (approximately)
sergejj [24]3 years ago
3 0
Hope this helps, have a great day ahead!

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3 years ago
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sladkih [1.3K]

Answer:

The  kinetic energy is KE  =  7.59  *10^{10} \  J

Explanation:

From the question we are told that

       The  radius of the orbit is  r =  2.3 *10^{4} \ km  = 2.3  *10^{7} \ m

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where v is the speed of the satellite which is mathematically represented as

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substituting this into the equation

      KE  =  \frac{ 1}{2} *\frac{GMm}{r}

Now the gravitational force of the planet is mathematically represented as

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Where M is the mass of the planet and  m is the mass of the satellite

 Now looking at the formula for KE we see that we can represent it as

     KE  =  \frac{ 1}{2} *[\frac{GMm}{r^2}] * r

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substituting values

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