Answer:
See below
Explanation:
See attached diagram
280 km east then 190 km north
Use Pythagorean theorem to find the resultant displacement
d^2 = 280^2 + 190^2
d = 338.4 km
Angle will be arctan ( 190/280) = 34.16 °
Refrigerant-134a enters a compressor at 180 kPa as a saturated vapor with a flow rate of 0.35 m3/min and leaves at 900 kPa. The
power supplied to the refrigerant during the compression process is 2.35 kW. What is the temperature of R-134a at the exit of the compressor
1 answer:
Answer:
52.5°C
Explanation:
The final enthalpy is determined from energy balance where initial enthalpy and specific volume are obtained from A-12 for the given pressure and state
mh1 + W = mh2
h2 = h1 + W/m
h1 + Wα1/V1
242.9 kJ/kg + 2.35.0.11049kJ/ 0.35/60kg
=287.4 kJ/kg
From the final enthalpy and pressure the final temperature is obtained A-13 using interpolation
i.e T2 = T1 + T2 -T1/h2 -h1(h2 - h1)
= 50°C + 60 - 50/295.15 - 284.79
(287.4 - 284.79)°C
= 52.5°C
You might be interested in
Answer:
The speed is 29.9 m/s
Explanation:
The force created from gravity due to the wagon mass is:
140.55 N pull the wagon down. Two parallel rope with tension of 191N creates 382 N on the wagon. Therefore:
241.45 N force is pulling up the wagon. Then we need to find the acceleration of the wagon under this force:
acceleration is 5.34 m/s^2. The distance is multiplication of acceleration and square of the time.
After 5.6 second the wagon will ride 83.8 m up to hill. And the speed of wagon at that point is: