Answer:
a)The direction the frictional force will acts is in the positive x direction.
Explanation:
a)The direction the frictional force will acts is in the positive x direction
b)in the horizontal direction, the total force F(total) is equal to 4times the frictional force in the wheel.
F(total)=4f
''f'' is taken as the frictional force.
c)4times the normal force on each wheel minus the acceleration equals zero i.e 4N(wheel)-a=0
=4N(wheel)-mg=0
d) torque is the force that tends to bend rotation
ζ=rf
but acceleration=4×frictional force
cross multiply
f=ζ/r
f=ma/4
ma/4=ζ/r
a=4ζ/r
Answer:46.05 mm
Explanation:
Given

speed 
allowable shear stress 
Power is given by



From Torsion Formula

where J=Polar section modulus
T=Torque
=shear stress
For square cross section

where a=side of square

Substituting the values in equation 1



Answer:
0.08 N/C
Explanation:
Electric Field: This is defined as the force per unit charge exerted at a point. The expression for electric field is given as,
E = Kq/r².............................. Equation 1
Where E = Electric Field, q = Charge, k = proportionality constant, r = distance.
making q the subject of the equation,
q = Er²/k............................... Equation 2
Given: E = 2 N/C, r = 4 m,
Substitute into equation 2
q = 2(4)²/k
q = 32/k C.
When r is increased to 20 m,
E = k(32/k)/20²
E = 32/400
E = 0.08 N/C.
Hence the electric Field = 0.08 N/C
The velocity of the block leaving the spring is determined as 18.26 m/s.
<h3>
Velocity of the block</h3>
The velocity of the block leaving the spring is calculated from the principle of conservation of energy.
K.E = Ux
¹/₂mv² = ¹/₂kx²
v² = kx²/m
v² = (500 x 2²)/6
v² = 333.33
v = √333.33
v = 18.26 m/s
Thus, the velocity of the block leaving the spring is determined as 18.26 m/s.
Learn more about velocity here: brainly.com/question/4931057
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Use the kinematic equation,
Vf^2 = Vi^2 + 2aX
31.5^2 = 11.6^2 + 2(5.22)(x)
Solve for x
Answer: 82.2m