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vivado [14]
3 years ago
7

Particles that attract each other are

Physics
2 answers:
Flura [38]3 years ago
8 0
D. hope it gets you the correct answer
photoshop1234 [79]3 years ago
3 0
B. I belive :)
Hopes this helps
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Does uniform circular motion have constant acceleration?
AysviL [449]
Yes. It's (speed squared)/(radius of the circle).
7 0
3 years ago
Container A and container B hold samples of the same ideal gas. The volume and the pressure of container A is equal to the volum
SVETLANKA909090 [29]

Answer:

A. TA = TB/2.

Explanation:

Since container A has half as many molecules of the ideal gas in it as container B. Therefore, container A will have half the volume of gas as in container B:

V_A = \frac{1}{2}V_B

Now, from Charle's Law:

\frac{V_A}{T_A}=\frac{V_B}{T_B}\\\\\frac{1}{2}\frac{V_B}{T_A}=\frac{V_B}{T_B}\\\\T_A = \frac{T_B}{2}

Hence, the correct option is:

<u>A. TA = TB/2.</u>

6 0
3 years ago
A wave has a wavelength of 125 meters is moving at a speed of 20 m/s. What is it frequency? ​
umka21 [38]

Answer:

0.16 Hz

Explanation:

frequency = speed/wavelength

= 20/125 = 0.16 Hz

3 0
3 years ago
If you can not see clearly 100 ft in both directions when approaching an uncontrolled intersection, what should your rate of spe
Lisa [10]

Answer:

15 MPH or less than that

Explanation:

You shouldn't drive faster than 15 MPH so if a truck unexpectedly pulls out you'll have time to stop.

When parked cars, branches of the tree, fences, houses, or other things block your vision of an open intersection, you can pause before approaching the junction and move slowly ahead until you can see if there is cross-traffic before moving through the junction.

7 0
4 years ago
Three forces act on an object. Two of the forces have the magnitudes 56 N and 27 N, and make angles 53° and 156°, respectively,
Ludmilka [50]

Answer:

Explanation:

Given

Two forces F_1 and F_2 at an angle of \theta _1  \theta _2

F_1=56\ N

F_2=27\ N

\theta _1=53^{\circ}

\theta _2=156^{\circ}

As resultant force is zero therefore horizontal component as well as vertical component of force is zero

\sum F_x=F_1\cos \theta _1+F_2\cos \theta _2+F_3\cos \theta _3

\sum F_x=56\cos 53+27\cos 156+F_3\cos \theta

F_3\cos \theta_3=-9.035\ N----1

\sum F_y=F_1\sin \theta _1+F_2\sin \theta _2+F_3\sin \theta _3

F_3\sin \theta _3=55.704\ N----2

squaring and adding 1 and 2

F_3^2(\cos ^2\theta _3+\sin^2\theta _3)=86.583+3102.93

F_3=56.47\ N

Divide 1 and 2 to get \theta _3

\frac{\sin \theta_3 }{\cos \theta_3 }=\frac{-55.704}{9.305}

\tan \theta_3=-6.16

\theta _3=180-80.78

\theta _3=99.22^{\circ}

 

6 0
3 years ago
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