Answer:
29011144
Step-by-step explanation:
It would be 1000 since the 2 is not bug enough to carry it over.
Answer:
If hours is represented as h, your distance is therefore 3*h (due to that for every hour, you walk 3 miles. For example, in one hour you'd walk 3 miles, in 2 hours you'd walk 3+3=3*2=6 miles,etc.). If distance is represented by d, we get 3*h=d. Since you have to figure out the distance from the equation (that's the purpose of it!), the distance is the dependent variable. In addition, since you can't have 2 separate variables in one equation, h is the independent variable due to that you have to put a number for h in to figure out the distance
So basically the answer is A.
The difference in the price per bag for 150 bags versus 50 bags is $0.05 per bag
<h3>What is an
equation?</h3>
An equation is an expression that shows the relationship between two or more variables and numbers.
From the diagram:
Price for 150 bag = $38
Cost per bag = $40 / 150 = $0.25
Also:
Price for 50 bag = $15
Cost per bag = $15 / 50 = $0.30
Difference in price = $0.30 - $0.25 = $0.05
The difference in the price per bag for 150 bags versus 50 bags is $0.05 per bag
Find out more on equation at: brainly.com/question/2972832
<h3><u>Option A</u></h3>
is the required equation to calculate width of rectangular frame that has a total area of 140 square inches.
<h3>
<u>Solution:</u></h3>
Given that,
Length of a rectangular frame is given as 2x + 10
Width of the rectangular frame is given as 2x + 6
Total area = 140 square inches
<em><u>The area of rectangular frame is given as:</u></em>

Plugging in values, we get

This is the required equation to calculate width of rectangular frame
Solve the above quadratic equation to get the value of "x"

<em><u>Use the quadratic equation formula:</u></em>

Here a = 4 ; b = 32 ; c = -80


x = 2 or x = -10
Now measurement cannot be negative, so taking the positve value of "x", we can calculate the width
So put "x" = 2
Width of the rectangular frame = 2x + 6 = 2(2) + 6 = 10
Thus the width of frame is 10 inches