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77julia77 [94]
3 years ago
5

How does the orientation of the image of the triangle compare with the orientation of the preimage?

Mathematics
1 answer:
Studentka2010 [4]3 years ago
8 0

The complete question is:

Joni translates a right triangle 2 units down and 4 units to the right. How does the orientation of the image of the triangle compare with the orientation of the preimage?

The orientation (will/will not) be the same.

Answer:

  • <u><em>The orientation will be the same</em></u>

Explanation:

The <em>orientation</em> of a figure is described by the angles of its sides with respect to some cartesian axis system.

The figure is said to be translated.

<em>Translation</em> consits in sliding the figure without changing the orientation: all the angles with respect to the original axis system remain unchanged.

When <em>Joni translates a right triangle 2 units down and 4 units to the right</em>, the triangle is just shifted down and to the right, but the <em>orientation </em>will not change; it <em>will remain the same</em>.

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Y - 4 = -3 ( x - 3 )<br> rewrite in y = mx+b
evablogger [386]

Answer:  y = -3x + 13

Step-by-step explanation:

y - 4 = -3(x-3)

y - 4 = -3x + 9

y = -3x + 13

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3 years ago
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What value of x makes this inequality true?<br> x+9 &lt; 4x
wariber [46]

Answer:

X>3

Step-by-step explanation:

X+9<4X

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3<x

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3 years ago
What is the sample space for a single toss of a number cube?
valina [46]

Answer:

6

Step-by-step explanation:

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6 0
3 years ago
High School Pre Cal
krok68 [10]
We know that
1) Sandra can run a mile in 6 minutes-------> 6*60-----> 360 sec
2) 4 laps around the track equals 1 mile
so
4 laps around the track in 360 sec
1 lap in 360/4--------> 90 sec
3) the position of Sandra for t=90 sec must be equal to the point S (0,56)
I proceed to analyze each case for t=90 sec

case a) x(t)=-140 cos(pi*t/45)    y(t)=112 sin(pi*t/45)
x(t)=-140 cos(pi*90/45)------> -140
y(t)=112 sin(pi*90/45)-------> 0
the position is the point (-140,0)------> is not the point S

case b) x(t)=140 sin(pi*t/90)  y(t)=-112 cos(pi*t/90)

x(t)=140 sin(pi*90/90)------> 0
y(t)=-112 cos(pi*90/90)-------> 112
the position is the point (0,112)------> is not the point S
<span>
case c) x(t)=-70 sin(pi*t/45)  y(t)=56 cos(pi*t/45)
</span>x(t)=-70 sin(pi*90/45)------> 0
y(t)=56 cos(pi*90/45) -------> 56
the position is the point (0,56)------> is equal to the point S----> is the solution

case d) x(t)=70 cos(pi*t/90)  y(t)=-56 sin(pi*t/90)

x(t)=70 cos(pi*90/90)------> -70
y(t)=-56 sin(pi*90/90)-------> 0
the position is the point (-70,0)------> is not the point S

 therefore

the answer is the option C

x(t)=-70 sin(pi*t/45)  y(t)=56 cos(pi*t/45)


7 0
3 years ago
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this is the inverse function of the given.......

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