Answer:
5m/s/s
Explanation:
10N bc you subtract 10N from 20N and you get 10
a=f/m
F=10N
m=2kg
10/2=5
To solve this problem it is necessary to apply the related concepts to string vibration. This concept shows the fundamental frequency of a string due to speed and length, that is,

Where
v = Velocity
L = Length
Directly if the speed is maintained the frequency is inversely proportional to the Length:

Therefore the relationship between two frequencies can be described as


Our values are given as,

Therefore the second frequency is

The frequency allocation of 329Hz is note E.
Given:
The length of the string is l = 6 m
The speed of the wave is

Required: Lowest possible frequency for the standing wave.
Explanation:
The lowest possible frequency is the fundamental frequency.
The fundamental frequency can be calculated by the formula

On substituting the values, the fundamental frequency will be

Final Answer: The lowest possible frequency for standing waves on this string is 16.67 Hz
Answer:
This is because the force of gravity is much less on the moon than on the earth, therefore the person wont be pulled down much and will jump higher