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Nookie1986 [14]
2 years ago
14

The total length of the wire of potentiometer is 10m. A potential gradient of 0.0015 V/cm is obtained when a steady current is p

assed through this wire.
Calculate,

i) the distance of null point on connecting a cell of emf 1.018 v

ii) the unknown P.d. if null point is obtained at 940 cm.​
Physics
1 answer:
andreyandreev [35.5K]2 years ago
3 0

Answer:

this picture might help you

Explanation:

if you think correct pls mark brainliest

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How many air molecules are in a 13.0×12.0×10.0 ft room (28.2 L=1 ft3)? Assume atmospheric pressure of 1.00 atm, a room temperatu
aksik [14]

Answer:

1963.93 Moles

Explanation:

-We know the standard conversion ratio for the volume of a mole is 1 Mole=22.4L

Given volume of rooms as 13.0ft\times12.0ft\times10ft=1560 ft^3

Convert the volume into liters:1560\times28.2l=43992l

#From our conversion ratio above, we get the volume of air molecules in moles as:

V_m=\frac{43992L}{22.4L}\times 1\ mole\\\\=1963.93\ Moles

Hence, the volume of air molecules is 1963.93 Moles

4 0
3 years ago
What are significant figures?
vekshin1
“The term significant figures refers to the number of important single digits (0 through 9 inclusive) in the coefficient of an expression in scientific notation . The number of significant figures in an expression indicates the confidence or precision with which an engineer or scientist states a quantity.”
8 0
3 years ago
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Which of the following materials used by plants to make food can be found in the air?
Rashid [163]

Answer:

<em><u>number</u></em><em><u> </u></em><em><u>d</u></em>

Explanation:

<em><u>because</u></em><em><u> </u></em><em><u>plant</u></em><em><u> </u></em><em><u>need</u></em><em><u> </u></em><em><u>carbondioxide</u></em>

5 0
2 years ago
Hi :) how to do this?
fredd [130]

Answer:

The answer is b

Hope this helps you!

4 0
3 years ago
The dimensions of aluminum foil in a box for sale in super markets are 66 2/3 yards by 12 inches. the mass of the foil is 0.83 k
disa [49]

Length of the sheet is given as

L = \frac{200}{3} yards = 6096 cm

width of the sheet is given as

w = 12 inches = 30.48 cm

now let say its thickness is "t"

so the volume of the sheet is given as

V = L*w*t

V = 6096*30.48* t

V = 185806.08*t cm^3

mass of the sheet is given as

m = 0.83 kg = 830 gram

now we have

density = \frac{mass}{volume}

2.70 = \frac{830}{185806.08*t}

by solving above we have

t = 1.65 * 10^{-3} cm

so the thickness of sheet will be above

4 0
3 years ago
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