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BARSIC [14]
3 years ago
11

Your friend says that when someone drives a car, they use up energy. You know that this isn’t quite true. Develop an argument ag

ainst your friend’s claim that uses scientific evidence. Be sure to include the vocabulary: energy transformation, Law of Conservation of Energy.
Physics
2 answers:
Dafna11 [192]3 years ago
3 0

Answer:

Only about 12%–30% of the energy from the fuel you put in a conventional vehicle is used to move it down the road, depending on the drive cycle.

Explanation:

Oksanka [162]3 years ago
3 0
You can say that the law of the conservation of energy states that energy cannot be created or destroyed only transferred. therefore the energy your friend said is used up is just simply transferred into other forms of energy
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The answer is D. Mountains in North America appear to be the same as those in Northern Europe
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4 years ago
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The rate at which light energy is radiated from a source is measured in which of the following units?
Tamiku [17]
The correct answer is A. Lumen

This is the so called energy of light measurement. Other mentioned measurements are used for different things such as measuring light over an area of space or similar.
6 0
3 years ago
Un móvil con velocidad inicial de 19,8km/h adquiere una aceleración constante de 2,4m/s^2. Determine la velocidad y el espacio r
nata0808 [166]

Responder:

Velocidad = 41.5m / s

Espacio recorrida = 352.5 metros

Explicación:

Dado lo siguiente:

Velocidad inicial (u) = 19.8 km / h

Aceleración (a) = 2.4m / s ^ 2

Tiempo de viaje (t) = 15 s

A.) velocidad después de 15 s

Velocidad inicial = (19.8 × 1000) m / 3600s Velocidad inicial = 19800m / 3600 = 5.5m / s

Usando la ecuación: v = u + at, donde v es la velocidad

v = 5.5 + 2.4 (15)

v = 5.5 + 36

v = 41.5m / s

Espacio recorrida:

v ^ 2 = u ^ 2 + 2aS; donde S es la distancia recorrida

41.5 ^ 2 = 5.5 ^ 2 + 2 × (2.4) × S

1722.25 = 30.25 + 4.8S

1722.25 - 30.25 = 4.8S

1692 = 4.8S S = 1692 / 4.8 S = 352.5m

8 0
3 years ago
Help in question a and b
Mkey [24]
Can you write out the question please? :) Sorry, i don't see it on the paper
8 0
3 years ago
given the data 11.4, 11.3, 11.2 and 11.1 cm determine the average and its standard deviation using equation
Ostrovityanka [42]

Answer:

Average  \bar{x} = 11.25 cm

standard deviation = 0.129 cm

Explanation:

The data provided in the question is:

x₁ = 11.4 cm

x₂ = 11.3 cm

x₃ = 11.2 cm

x₄ = 11.1 cm

total number of data points, N = 4

Now, the average is calculated as:

Average \bar{x} = \frac{sum\ of\ all\ the\ data\ points }{number\ of\ data\ points}

substituting the values in the above formula we get,

Average  \bar{x} = \frac{11.4cm+11.3cm+11.2cm+11.1cm }{4}

Average  \bar{x} = 11.25 cm

Now the standard deviation is calculated as:

standard deviation = \sqrt\frac{\sum_{i=1}^{4} \left(x_i - \bar x \right )^2}{N-1}

substituting the values in the above equation we get,

standard deviation = \sqrt\frac{\left(11.4 - 11.25 \right )^2 + \left(11.3 - 11.25 \right )^2 + \left(11.2 - 11.25 \right )^2 + \left(11.1 - 11.25 \right )^2}{3}

or

standard deviation = 0.129 cm

5 0
3 years ago
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