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Elan Coil [88]
3 years ago
7

(2x -2)^-3can anyone help me with this?​

Mathematics
1 answer:
zzz [600]3 years ago
4 0

Answer: See below

Step-by-step explanation:

When you see that something is to the power of a negative number, it is another way of saying 1 over.

(2x-2)^-^3=\frac{1}{(2x-2)^3} =\frac{1}{(2x-2)(4x^2-8x+4)} =\frac{1}{8x^3-8x^2+8x-8}

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C. y= 6.18x + 10.9

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Step-by-step explanation:

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        --------------

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What is the value of this expression when a = 4, b = -5, and c = -7?
Ganezh [65]

Answer:

The value of the given expression is -878.08.

Step-by-step explanation:

Here, the given question is INCOMPLETE.

The complete question is:

Evaluate the expression for a = 4, b = -5, and c = -7. 4a^2b^{-2}c^3

Here, substitute the vale of a  = 4, b = -5 and c = -7, we get:

4a^2b^{-2}c^3  = (\frac{4a^2c^3}{b^2})  =  (\frac{4(4)^2(-7)^3}{(-5)^2})\\= (\frac{64 \times 343}{25})   =\frac{21,952}{25} =   878.08\\\implies 4a^2b^{-2}c^3 =   878.08 ( a = 4, b = -5 ,c = -7)

Hence, the value of the given expression is -878.08.

8 0
3 years ago
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