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2 years ago

(2x -2)^-3can anyone help me with this?

Mathematics

1 answer:

zzz [600]2 years ago

4 0

Answer: See below

Step-by-step explanation:

When you see that something is to the power of a negative number, it is another way of saying 1 over.

$(2x-2)^-^3=\frac{1}{(2x-2)^3} =\frac{1}{(2x-2)(4x^2-8x+4)} =\frac{1}{8x^3-8x^2+8x-8}$

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HELP ASAPPPP !!!!!!!!!!!......

irina [24]

Answer:

just use a calculator

8 0

2 years ago

Which values of x would make a polynomial equal to zero if the factors of the polynomial were (x-5) and (x-6)

meriva

x-5= 0

move -5 to the other side

sign changes from -5 to +5

x-5+5= 0+5

x= 5

x-6= 0

x-6+6= 0+6

x= 6

Answer: B. 5 and 6

5 0

2 years ago

Read 2 more answers

On a farm the number of cows and the number of sheep are in the tatio 6:5 the number of sheep and the number of pigs are in the

Rzqust [24]

Answer:

There are 70 sheep in the farm.

Step-by-step explanation:

Consider the provided information.

Let c represents the cows, s represents the sheep and p represents the pigs.

The number of cows and the number of sheep are in the ratio 6:5.

$\dfrac{c}{s} =\dfrac{6}{5}$

$c =\dfrac{6s}{5}$

The number of sheep and the number of pigs are in the ratio 2:1.

$\dfrac{s}{p} =\dfrac{2}{1}$

$p =\dfrac{s}{2}$

The total number is 189.

$c+s+p=189$

Substitute the value of c and p in above.

$\dfrac{6s}{5}+s+\dfrac{s}{2}=189$

$\dfrac{12s+10s+5s}{10}=189$

$27s=1890$

$s=70$

Hence, there are 70 sheep in the farm.

8 0

3 years ago

On a piece of paper, graph y+2>-3x - 3. Then determine which answer

zmey [24]

Answer:

Step-by-step explanation:

【Look at the image】

7 0

2 years ago

Read 2 more answers

Harmonic mean if a number h such that (h-a)/(b-h)=a/b Prove h is H(a,b) iff satisfies either relation a. (1/a)-(1/h) = (1/h) - (

Fudgin [204]

A.

$\displaystyle\frac1a-\frac1h=\frac1h-\frac1b$
$\implies\displaystyle\frac{h-a}{ah}=\frac{b-h}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac{ah}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac ab$

b.

$\displaystyle h=\frac{2ab}{a+b}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{\frac{2ab}{a+b}-a}{b-\frac{2ab}{a+b}}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{2ab-a(a+b)}{b(a+b)-2ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{ab-a^2}{b^2-ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{a(b-a)}{b(b-a)}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac ab$

The other direction can be proved by following the manipulations in the reverse order.

7 0

2 years ago

(2x -2)^-3can anyone help me with this?​

(2x -2)^-3can anyone help me with this?