Answer: bromine
Explanation: Thus bromine would release most energy while adding an an electron to a neutral atom in the gas phase.
The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively
Data;
- Volume of solution = 260mL
- conc. of HCHO2 = 2.5*10^-2M
- conc. of NaCHO2 = 2.5*10^-2M
<h3>Mass of Reagent Added</h3>
To calculate the mass of reagent added, let's start with HCHO2
The mass of HCHO2 to be added is the number of moles of HCHO2 multiplied by it's molar mass.
The mass of NaCHO2 to be added in the buffer solution is
The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively
Learn more about buffer solution here;
brainly.com/question/22390063
Answer:
0.271 M NO₃⁻
Explanation:
To find the molarity of the nitrate ion (NO₃⁻), you need to (1) convert grams to moles (via molar mass), then (2) convert moles Al(NO₃)₃ to moles NO₃⁻, then (3) convert mL to L, and then (4) calculate the molarity. When (Al(NO₃)₃) dissolves in water, it dissociates into 3 nitrate ions. The final answer should have 3 sig figs.
(Steps 1 + 2)
Molar Mass (Al(NO₃)₃): 26.982 g/mol + 3(14.007 g/mol) + 9(15.998 g/mol)
Molar Mass (Al(NO₃)₃): 212.985 g/mol
1 Al(NO₃)₃ = 1 Al³⁺ and 3 NO₃⁻
6.25 g Al(NO₃)₃ 1 mole 3 moles NO₃⁻
------------------------- x ----------------- x ----------------------- = 0.0880 moles NO₃⁻
212.985 g 1 mole Al(NO₃)₃
(Steps 3 + 4)
325.0 mL / 1,000 = 0.3250 L
Molarity = moles / volume
Molarity = 0.0880 moles / 0.3250 L
Molarity = 0.271 M
