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1 year ago

The incomplete table below shows selected properties of compounds that have ionic, covalent, or metallic bonds.

Chemistry

1 answer:

pogonyaev1 year ago

8 0

Answer:

is there an option for silver? if so, silver is the answer.

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Rosa drew a flow chart of the carbon cycle.

Lisa [10]

The correct Answer is A.

The Flow chart of the Carbon Cycle, will look as follows:

1. Carbon dioxide in the atmosphere.

2. Producers undergo photosynthesis (in this process plants among other producers like algae, use CO2 to produce energy).

3. Consumers eat producers (a primary level of consumer like a rabbit eats the producers or plants).

4. Decomposers return Carbon to the soil and release waste.

And the cycle continues again, by going back to step 1.

7 0

3 years ago

Read 2 more answers

The reaction of 5.40 g of carbon with excess O2 yields 13.6 g of CO2. What is the percent yield of this reaction?

vazorg [7]

C + O2= CO2
$n = \frac{m}{mw}$
$n = \frac{5.4}{12} \\ n = 0.45 \: mol \: of \: carbon$
$n = \frac{13.6}{12 + 16 \times 2} \\ n = \frac{13.6}{44} \\ n = 0.31 \: mol \: of \: carbon \: dioxide$
CO2 is limit
5.4-3.72= 1.68 g of C is excess
5.4 g = 100%
3.72 g = x
x=68.9 %

4 0

3 years ago

Question 4 need this answered asap (chemistry)

aleksandrvk [35]

Answer:

Conductivity meter

Explanation:

All of the other choices measure pH and can tell you when the pH changes, which is how you know the neutralization reaction has occurred. A conductivity meter does not measure pH.

3 0

3 years ago

Which provides a baseline for an experimental investigation

Goryan [66]

Answer:

control group

Explanation:

7 0

3 years ago

Part A of the lab involved adding 4 mL increments of distilled water to 5.00 mL of antimony trichloride solution. The antimony t

Mrrafil [7]

Answer:

0.0238M SbCl3, 1.07M H+, 1.14M Cl-

Explanation:

The total volume of the solution is:

4mL + 5.00mL + 12.0mL = 21mL

As the volume of the SbCl3 is 5.00mL, the dilution factor is:

21mL / 5.00mL = 4.2 times

The concentration of SbCl3 is:

0.10M SbCl3 / 4.2 times = 0.0238M SbCl3

The concentration of H+ = [HCl]:

4.5M / 4.2 times = 1.07M H+

The initial concentration of Cl- is:

3 times SbCl3 + HCl = 0.10M*3 + 4.5M =

<em>3 times SbCl3 because 1 mole of SbCl3 contains 3 moles of Cl-</em>

4.8M Cl- / 4.2 times = 1.14M Cl-

3 0

2 years ago