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o-na [289]
3 years ago
11

What is paper chromatography? Calculate the Rr value of a colored dye that traveled 52 mm on a chromatography strip while the so

lvent front traveled 81 mm.

Chemistry
1 answer:
Karo-lina-s [1.5K]3 years ago
3 0

Answer:

Paper chromatography is a basic technique of chromatography. It consist in the separation of the mixe components using a solvent.

Explanation:

Paper chromatography is a basic technique of chromatography. It consists in the separation of the mixed components using a solvent.

Paper chromatography consists of put some dot of the mix using a glass capillary into a specialized paper, generally made of cellulose, this is called a stationary phase.

Then you put this paper into a camera of glass named, chromatography camera, where previously contain a solvent. The solvent also know as a mobile phase, the type can be defined before the test and involves a study of the kind of the mix, and the compound you want to separate.

The chromatography camera has to be closed all the time during the test, and you can't move at all because the movement of the solvent can alternate the result.

Very often, the solution of the solvent is a mix of different liquid substances with different polarities.

When the stationary phase put into the camera, the solvent starts to move up over the paper, until the separation of the compounds is observable.

the Rf is a value who relates the move of the mobile phase with the move of the distance traveled by the substance tested.

To undersant the paper chromatography, you can watch the images attached.

The first is an image of the chromatography camera.

The second one is an image of a cellulose paper after the chromatography is done. You can watch the dots who indicates the traveling of the compound across the paper.

The third one can show you the evolutions of paper chromatography, from the beginning to the end.

To calculate the Rf value you have to use the equation:

Rf = distance traveled by the substance/distance traveled by the solvent/

<u>Rf = 52mm/81mm =0.64</u>

<u></u>

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A biologist working in a lab adds a compound to a solution that contains an enzyme and substrate. This particular compound binds
ad-work [718]

Answer:

Adding more substrate would overcome  the effect of the compound

Explanation:

  • Enzymes are biochemical catalysts that speed up chemical reactions. They act on specific substrate to convert them to products.
  • Compounds known as inhibitors slow down the rate of enzyme activity.
  • Inhibitors are classified as competitive and non-competitive inhibitors.
  • Competitive inhibitors will compete with the substrate to bind the active sites on the enzyme. The effect of competitive inhibitors may be reduced by increasing the concentration of the substrate.
  • The compound added by the biologist was a competitive inhibitor and therefore adding more substrate would overcome its effect on enzyme catalysis
  • Non-competitive inhibitors binds the active site of the enzyme permanently and prevents the substrate from accessing the active sites.

6 0
3 years ago
Is the bond C=O polar or non polar
rewona [7]

Answer:

Non Polar

Explanation:

Non Polar molecule because of its linear symmetric shape

6 0
3 years ago
a mixture contains two or more substances that are physically combined and there is no electron bonding
crimeas [40]


True.

A mixture is composed of two or more pure substance that are physically combined but are not combined chemically and thus no electrons (of their atoms) are involved.

The primary properties of a mixture include:

1. The components of a mixture are easily separated

2. The components each keep their original properties.

3. The proportion of the components may vary.

There are two main categories of mixtures:

1. Heterogeneous mixtures - substances are not evenly distributed e.g. oil and water mixture

2. Homogeneous mixtures - substances are evenly distributed throughout the mixture e.g. salt water, air. 




4 0
3 years ago
Calculate the mass of one mole of these substances.
pogonyaev

Answer:

a. 53.5 g/mol

b. 80.06 g/mol

c. 133.33 g/mol

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Molar Mass - 1 mol per <em>x</em> grams substance

Explanation:

<u>Step 1: Define</u>

a. NH₄Cl

b. NH₄NO₃

c. AlCl₃

<u>Step 2: Find masses</u>

Molar Mass of N - 14.01 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Al - 26.98 g/mol

Molar Mass of Cl - 35.45 g/mol

<u>Step 3: Calculate compound masses</u>

Molar Mass of NH₄Cl - 14.01 g/mol + 4(1.01 g/mol) + 35.45 g/mol = 53.5 g/mol

Molar Mass of NH₄NO₃ - 2(14.01 g/mol) + 4(1.01 g/mol) + 3(16.00 g/mol) = 80.06 g/mol

Molar Mass of AlCl₃ - 26.98 g/mol + 3(35.45 g/mol) = 133.33 g/mol

6 0
3 years ago
True or false: The number of protons an element has can vary.
Lerok [7]

Answer:

true

Explanation:

5 0
3 years ago
Read 2 more answers
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