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andrezito [222]
3 years ago
8

calculate the atomic mass of element X, if it has 2 naturally occurring isotopes with the following masses and natural abundance

:X-4544.8776amu 32.88% X-4746.9443amu67.12%​
Chemistry
1 answer:
jeka57 [31]3 years ago
4 0
Hey there!

To find this, you should:

1) multiply the percentage (but in a decimal form) of each isotope by the mass.
2) add all your masses together
3) make sure to check for significant figures and you’re done!

Hope this helps :)
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lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

           CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)

Calculate the amount of CO_{2} dissolved as follows.

             CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}

It is given that K_{CO_{2}} = 0.032 M/atm and P_{CO_{2}} = 1.9 \times 10^{-4} atm.

Hence, [CO_{2}] will be calculated as follows.

           [CO_{2}] = K_{CO_{2}} \times P_{CO_{2}}          

                           = 0.032 M/atm \times 1.9 \times 10^{-4}atm

                           = 0.0608 \times 10^{-4}

or,                        = 0.608 \times 10^{-5}

It is given that K_{a} = 4.46 \times 10^{-7}

As,      K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}

          4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}  

               [H^{+}]^{2} = 2.71 \times 10^{-12}

                      [H^{+}] = 1.64 \times 10^{-6}

Since, we know that pH = -log [H^{+}]

So,                      pH = -log (1.64 \times 10^{-6})

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Answer:

moles of glucose

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<u></u>

Explanation:

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here , CO2 = carbon dioxide

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According to this equation :

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We are asked to calculate the mole of Glucose from carbon dioxide.

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Note : first , Always calculate for one mole (By dividing)

. After this , multiply the answer with the moles given.

Always write the substance whose amount is asked(glucose) to the right hand side

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