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Ghella [55]
3 years ago
13

__________ brake systems release the brakes momentarily when wheel speed sensors indicate a locked wheel during braking and trac

tion. Control systems apply the brakes momentarily to one of the drive wheels whenever the wheel speed sensors indicate a wheel is going faster than the others during acceleration.
Physics
2 answers:
nasty-shy [4]3 years ago
6 0

Answer:

Anti- Lock

Explanation:

Anti- lock brake systems(ABS) is a safety system used in hindering the wheels from locking up when the brake is applied.

Braking release the brakes momentarily when wheel speed sensors indicate a locked wheel during braking and traction.

Control systems apply the brakes momentarily to one of the drive wheels whenever the wheel speed sensors indicate a wheel is going faster than the others during acceleration.

chubhunter [2.5K]3 years ago
5 0

"Anti-Lock" brake systems release the brakes momentarily when wheel speed sensors indicate a locked wheel during braking and traction.

<u>Explanation:</u>

The safety anti-skid braking system is known as "anti-lock braking system" having huge application on land vehicles like one, two and multiple wheeler vehicles and aircraft. During braking, it avoids wheels to get locked by building tractive contacts to the road's surface.

This seems to be an automated system work on the principles of techniques - threshold and cadence braking. The wheel velocity sensors are utilized by ABS to find whether one or more than one wheels chose to get lock while braking.

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3 years ago
Starting from rest, a 75.0-kg snowboarder slides straight down a 115-m slope in 6.6 s. If the slope is a 35°
Likurg_2 [28]

The acceleration of the snowboarder is 5.6 m/s^2 down along the incline

Explanation:

To find the acceleration of the snowboard, we have to analyze the forces acting along the direction parallel to the incline.

There is only one force acting in this direction, and it is the component of the weight parallel to the incline, given by

mg sin \theta

where

m = 75.0 kg is the mass of the man

g=9.8 m/s^2 is the acceleration of gravity

\theta=35^{\circ} is the angle of the incline

Substituting, we find that the net force along the incline is:

F=(75.0)(9.8)(sin 35^{\circ})=421.6 N

According to Newton's second law, the net force on the snowboard is equal to the product between his mass and his acceleration:

F=ma

where a is the acceleration. Therefore, solving for a, we find

a=\frac{F}{m}=\frac{421.6}{75}=5.6 m/s^2

And the direction of this acceleration is down along the incline.

Learn more about acceleration and Newton's second law:

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8 0
3 years ago
A 5 kg mass is moving at 3 ms-1. Calculate its kinetic energy.
cupoosta [38]

Answer:

1/2 MV squared

1/2*5*3 squared

=22.5

8 0
3 years ago
A uniform electric field of magnitude 4.9 ✕ 10^4 N/C passes through the plane of a square sheet with sides 8.0 m long. Calculate
3241004551 [841]

Answer:

1.  1.568 x 10^6 N m^2 / C

2. -  1.568 x 10^6 N m^2 / C

Explanation:

E = 4.9 x 10^4 N/C

Side of square, a = 8 m

Area, A = side x side = 8 x 8 = 64 m^2

Angle between lane of sheet and electric field = 30°

Angle between the normal of plane of sheet and electric field,

θ = 90°- 30° = 60°

The formula for the electric flux is given by

\phi = E A Cos\theta

(1) \phi = E A Cos\theta

By substituting the values, we get

Ф = 4.9 x 10^4 x 64 x Cos 60 = 1.568 x 10^6 N m^2 / C

(2) \phi = E A Cos\theta

By substituting the values, we get

Ф = - 4.9 x 10^4 x 64 x Cos 60 = - 1.568 x 10^6 N m^2 / C

6 0
3 years ago
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