Question

The combustion of titanium with oxygen produces titanium dioxide: ti (s) + o2(g) â tio2 (s) when 1.000 g of titanium is combusted in a bomb calorimeter, the temperature of the calorimeter increases from 25.00 °c to 60.00 °c. in a separate experiment, the heat capacity of the calorimeter is measured to be 9.84 kj/k. the heat of reaction for the combustion of a mole of ti in this calorimeter is ________ kj/mol.

Answer 1

Answer:

The heat of reaction for the combustion of a mole of Ti in this calorimeter is -16,557.69 kJ/mol.

Explanation:

Mass of  titanium = 1.000 g

Moles of titanium =$\frac{1 g}{47.87 g/mol}=0.0208 mole$

Heat capacity of the calorimeter ,c= 9.84 kJ/K

Initial temperature of the calorimeter ,T=25°C =298 K

Final temperature of the calorimeter ,T'= 60°C = 333 K

Heat gained by calorimeter = q

$q=c\times \Delta T= 9.84 kJ/K\times(333K-298 K)=344.4 kJ$

Heat of combustion released when 1 g of titanium = -344.4 kJ

Heat if released that is why negative sign is used.

In 1 g of titanium = 0.0208 mole

Heat of combustion of 0.0208 moles of titanium = -344.4 kJ

Heat of combustion of 1 moles of titanium:

$\frac{-344.4 kJ}{0.0208}=-16,557.69 kJ$

The heat of reaction for the combustion of a mole of Ti in this calorimeter is -16,557.69 kJ/mol.

Answer 2

I think it is 1.2  i hope it helps