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Serjik [45]
3 years ago
8

Identity the anode and cathode

Chemistry
1 answer:
Anna007 [38]3 years ago
7 0

Answer:

Pb(s) ---> Pb+2 + 2e- is the anode

Cu+2(aq) + 2e- ---> Cu(s) is the cathode

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Energy is released when the nucleus of an atom splits and two smaller atoms are formed. What is the name of this process?
Svetllana [295]

Explanation:

It's (D), nuclear fission................

5 0
3 years ago
An aqueous magnesium chloride solution is made by dissolving 7.15 moles of MgCl2 in sufficient water so that the final volume of
irinina [24]

Answer:

2.86mol/L

Explanation:

Given parameters:

Number of moles of MgCl₂  = 7.15moles

Volume of solution  = 2.50L

Unknown:

Molarity of the MgCl₂ solution = ?

Solution:

The molarity of a solution is the number of moles of solute found in a given volume.

  Molarity  = \frac{number of moles }{volume}  

 Insert the parameters and solve;

   Molarity  = \frac{7.15}{2.5}   = 2.86mol/L

4 0
3 years ago
1. A 2-kg bowling ball sits on top of a building that is 40 meters tall. (5 pts) Circle one: KE / GPE / both ( can you show work
masha68 [24]
Potential energy is energy due to an object's height above the ground.
Potential energy = mass x gravity x height
Kinetic energy is energy due to the motion of the object.
Kinetic energy = 1/2 x mass x velocity²

1.
The ball is not moving and is at a height above the ground so it has only potential energy.
P.E = 2 x 9.81 x 40
P.E = 784.8 J

2.
The ball is moving and has a height above the Earth's surface so it has both kinetic and potential energy.
P.E = same as part 1 = 784.8 J
K.E = 1/2 x 2 x 5²
K.E = 25 J

3.
The ball has no height above the Earth's surface and is moving so it has only kinetic energy.
K.E = 1/2 x 2 x 10²
K.E = 100 J

4.
50000 = 1/2 x 1000 x v²
v = 10 m/s

5.
39200 = 200 x 9.81 x h
h = 20.0 m

6.
12.5 = 1/2 x 1 x v²
v = 5 m/s
98 = 1 x 9.81 x h
h = 10.0 m
3 0
3 years ago
2C3H7OH + 9O2 --> 6CO2 + 8H2O
Ne4ueva [31]
<h3>Answer:</h3>

733 g CO₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced]   2C₃H₇OH + 9O₂ → 6CO₂ + 8H₂O

[Given]   5.55 mol C₃H₇OH

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol C₃H₇OH → 6 CO₂

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up conversion:                    \displaystyle 5.55 \ mol \ C_3H_7OH(\frac{6 \ mol \ CO_2}{2 \ mol \ C_3H_7OH})(\frac{44.01 \ g \ CO_2}{1 \ mol \ CO_2})
  2. Multiply/Divide:                                                                                               \displaystyle 732.767 \ g \ CO_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

732.767 g CO₂ ≈ 733 g CO₂

8 0
3 years ago
4. How would you calculate the poH of a base when given the<br><br> concentration of [OH]-?
Novay_Z [31]

Answer:

Use pOH = -log₁₀ [OH-]

Explanation:

pOH can be calculated from the concentration of hydroxide ions using the formular below:

pOH = -log₁₀ [OH-]

The pOH is the negative logarithm of the hydroxide ion concentration.

3 0
3 years ago
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