All categories

2 years ago

Wet chemical system components typically are a storage tank or tanks, piping, nozzles, and a(an)?

1 answer:

5 0

Wet chemical system components typically are a storage tank or tanks, piping, nozzles, and an actuating mechanism.

<h3>Which parts make up an actuation mechanism?</h3>

The typical components of an actuation mechanism include a motor, transmission, control units, feedback, signaling, interlocking, and shutdown units. An electrical, hydraulic, or pneumatic drive is used to move a valve, shutter, or gate, which acts as an actuator to regulate the flow of fluids or gases.

<h3>What is the operation of the operator-dependent actuating mechanism?</h3>

When an automatic clutch is engaged, the control system 2 replaces the target-value signals coming over feeders 1 with the operator force signal if the operator uses the operator-dependent actuating mechanism.

Learn more about automatic clutch here:-

brainly.com/question/8012302

#SPJ4

You might be interested in

I need half reactions, for the following equation.

zhuklara [117]

Answer : Half reaction is defined as the reaction which will be <span>either the oxidation or reduction </span>reaction<span> of particular species in a given redox </span>reaction<span>.

So as per the definition in the reaction of,

</span> $Ba + ZnSO_{4} ----\ \textgreater \ BaSO_{4} + Zn$
<span>
</span> $Ba_{(s)} + Zn ^{+2} + SO_{4}^{-2} = Ba^{+2} + SO_{4}^{-2} + Zn_{(s)}$
<span>
here on left and right side </span> $SO_{4}^{-2}$ will get cancelled.

and we will get, $Ba_{(s)} + Zn ^{+2} = Ba^{+2} + Zn_{(s)}$

Here,
$Ba_{(s)} ----\ \textgreater \ Ba^{+2} - 2e^{-}$ ...this is oxidation reaction as Ba is getting reduced to $Ba^{+2}$ by losing 2 electrons.

whereas,on the other hand, $Zn ^{+2} ----\ \textgreater \ Zn_{(s)} + 2e ^{-}$ ...this is reduction reaction as $Zn ^{+2}$ is getting reduced to Zn by gaining 2 electrons.

8 0

3 years ago

Selective breeding happens?

inysia [295]

Selective breeding, also known as artificial selection, is a process used by humans to develop new organisms with desirable characteristics. Breeders select two parents that have beneficial phenotypic traits to reproduce, yielding offspring with those desired traits.

5 0

3 years ago

A water treatment plant has 4 settling tanks that operate in parallel (the flow gets split into 4 equal flow streams), and each

ale4655 [162]

Answer:

a) When the 4 tanks operate in parallel the retention time is 1.26 hours.

b) If the tanks are in series, the retention time would be 0.31 hours

Explanation:

The plant has 4 tanks, each tank has a volume V = 600 $m_3$ . The total flow to the plant is Ft = 12 MGD (Millions of gallons per day)

When we use the tanks in parallel, it means that the total flow will be divided in the total number of tanks. F1 will be the flow of each tank.

Firstly, we should convert the MGD to $m_3 /day$ . In that sense, we can calculate the retention time using the tank volume in $m_3$ .

$Ft =12 \frac{MG}{day} (\frac{1*10^6 gall}{1MG} ) (\frac{3.78 L}{1 gall} ) (\frac{1 dm^3}{1L} ) (\frac{1 m^3}{10^3 dm^3} ) = 45360 \frac{m^3}{day}$

After that, we should divide the total flow by four, because we have four tanks.

$F1 = Ft/4 =(45360 \frac{m^3}{d} )/4 = 11 340 \frac{m^3}{d}$

To calculate the retention time we divide the total volume V by the flow of each tank F1.

$t1 =\frac{V1}{F1} = \frac{600 m^3}{11340 \frac{m^3}{d} } = 0.0529 day\\t1 = 0.0529 d (\frac{24 h}{1d} ) = 1.26 h$

After converting t1 to hours we found that the retention time when the four reactors are in parallel is 1.26 hours.

If the four reactors were working in series, the entire flow goes first through one tank, then the second and so on. It means the total flow will be the flow of each tank.

In that order of ideas, the flow for reactors in series will be F2, and will have the same value of F0.

F2 = F0

To calculate the retention time t2 we divide the total volume V by the flow of each tank F2.

$t2 =\frac{V1}{F2} = \frac{600 m^3}{45360 \frac{m^3}{d} } = 0.01 day\\t2 = 0.01 d (\frac{24 h}{1d} ) = 0.31 h$

After converting t2 to hours we found that the retention time when the four reactors are in series is 0.31 hours.

5 0

3 years ago

15 POINTS!!!

lawyer [7]

<em>Answer:</em>

At 60 centigrade, the kinetic energy of the substance will be greatest.

<em>Explanation:</em>

As we know, the kinetic energy of substance is directly proportional to Temperature.

The total Kinetic energy can be calculated as follow

K.E = 3/2 n.R.T

From the equations, it is cleared that Temperature is directly proportional to temperature.

7 0

3 years ago

Read 2 more answers

An atom of boron has an atomic number of 5 and an atomic mass of 11. The atom contains (2 points)

Nesterboy [21]

C) 5 protons, 5 electrons, and 6 neutrons

7 0

4 years ago