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IRISSAK [1]
3 years ago
8

If a simple machine reduces the strength of a force, what must be increased?. . A. the distance that the force move. . B. the wo

rk the simple machine performs. . C. the speed of the input force. . D. the size of the simple machine
Physics
2 answers:
anzhelika [568]3 years ago
6 0
<h3><u>Answer;</u></h3>

A. the distance that the force move

<h3><u>Explanation;</u></h3>
  • <em><u>Simple machines function to make work easier by reducing human effort. </u></em>These machines may<em><u> increase the strength of the force, or increase the distance over which the force applied or even change the direction in which the force is applied.</u></em>
  • Therefore, when these simple machine reduce strength of a force then the distance over which the force is applied or moves should be increased. <em><u>Examples of machines that makes work easier by increasing the distance over which the force is applied include, hammers and leaf rakes. </u></em>
Karolina [17]3 years ago
3 0
"The distance that the force moves" is the one among the following choices given in the question that must be increased, if <span>a simple machine reduces the strength of a force. The correct option among all the options that are given in the question is the first option or option "A". I hope the answer helped you.</span>
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Given:

3 times 10 to the 8th power can be expressed in equation format as 3 \times 10^{8} (3 times symbolizes ‘multiplication’ then it is to the tenth power of 8)

2.45 times 10 to the 9th power can be expressed in equation format as 2.45 \times 10^{9} (2.45 times symbolizes ‘multiplication’, then it is to the tenth power of 9)

Asked to find the solution when dividing the above,

                 \frac{3 \times 10^{8}}{2.45 \times 10^{9}}=\frac{3}{2.45} \times 10^{8-9}

When the tenth power of any value goes from denominator to numerator and vice-versa, presents in opposite sign to that it possess (like when ‘10^{9} ' goes to numerator changed as ' 10^{-9} ').

Now by solving the above equation, we get

                \frac{3}{2.45} \times 10^{8-9}=1.22 \times 10^{-1}=\frac{1.22}{10}=0.12244898

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