Under normal conditions, what color do we expect diamonds to be?

1 answer:

8 0

Under normal lighting conditions, most diamonds appear to be colorless the naked eye. Many consumers think that all diamonds are colorless, however, in reality, they come in a wide range of colors. Actualcolor differences are very subtle.

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Dwight pulls his sister in her wagon with a force of 65 N at an angle of 50.0º to the ground. What are the magnitudes of the hor

NeTakaya

Refer to the diagram shown.

F = 65 N, the force exerted by Dwight.

The horizontal component of the force is
65 cos(50°) = 41.8 N
The vertical component of the force is
65 sin(50°) = 49.8 N

Answer:
Horizontal: 41.8 N
Vertical: 49.8 N

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What is the change in velocity if the final velocity is 80 mph and the initial velocity is 20 mph? Is the object speeding up or

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attashe74 [19]

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3 years ago

Velocity vector and acceleration vector in a uniform circular motion are related as.

mr_godi [17]

They are related as $\bold{\underline {v}\,.\,\underline a }= \bold{0}$

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This speed is always directed along the tangent to the circle at a given point. (refer to the figure attached)
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In mathematics, 2 vectors ( $\underline p$ , $\underline q$ ) that are perpendicular to each other have a quality that their dot product ( $\underline p\,.\, \underline q$ ) equal to zero vector ( $\bold 0$ ) which is written as $\undeline p\,.\, \underline q = \bold 0$ .
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11 months ago

In the figure below the pulley is a solid disk of mass M and radius R with rotational inertia MR 2/2. Two blocks one of mass m a

matrenka [14]

Assuming you are looking for the acceleration a:

1. $m_1a = T_1 -m_1g$
2. $m_2a = m_2g - T_2$
where T is the tension and a is the acceleration of the blocks. The acceleration of the two blocks and the acceleration of the pulley must be equal.

The torque on the pulley is given by:
3. $\tau = \overrightarrow r \times \overrightarrow F = (T_2 - T_1)R = I\alpha = \frac{1}{2} MR^2 \frac{a}{R}$
where $I = \frac{1}{2} mR^2$ and $a = \alpha R$ .

Combining the three equations:
$T_2 - T_1 = \frac{1}{2} Ma \\ m_2g - m_2a -m_1g - m_1a = (m_2-m_1)g - (m_1 + m_2)a = \frac{1}2}Ma \\ \\ a = \frac{(m_2 - m_1)g}{m_1 + m_2 + \frac{1}{2}M }$

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3 years ago

Under normal conditions, what color do we expect diamonds to be?​

Under normal conditions, what color do we expect diamonds to be?