Question

City a and city b had two different temperatures on a particular day four times the temperature of city a was 8c more than 3 times the temperature of city b the temperature of city a minus twice the temperature of city b was -3c what was the temperature of city a and city b on that day

Answer 1

Answer:

The temperature of the city a was 5 °C and b was 4 °C.

Step-by-step explanation:

First we have to write the equations based on the description, this is:

$4a=8+3b\\a-2b=-3$

Now that we have the equations, we can replace the second in the first:

$4(2b-3)=8+3b$

Now we can find the value of b:

$8b-12=8+3b$

$8b-3b=8+12$

$5b=20$

$b=\frac{20}{5}$

$b=4$

Now with the value of b and the second equation we can get the value of a:

$a-2(4)=-3$

$a-8=-3$

$a=8-3$

$a=5$

The temperature of the city a was 5 °C and b was 4 °C.

Answer 2

Answer:

temperature of city a=5

temperature of city b=4

Step-by-step explanation:

Given:

Let temperature of city A= a

temperature of city B=b

As given:

4a=8+3b

a-2b=-3

rearranging 2nd equation we get:

a=-3+2b

substituting above in 1st equation we get:

4(-3+2b)-3b=8

8b - 12 = 3b + 8

8b-3b=12+8

5b = 20

b = 4

Now substituting b=4 in 4a = 8 + 3b , we get

4a = 8 + 3b

4a = 8 + 3(4)

4a = 8 + 12

4a = 20

a = 20/4

a = 5

temperature of city a and city b on that day is 5C and 4C respectively!