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1 answer:
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Explanation:
For the given reaction
Now, expression for half-life of a second order reaction is as follows.
....... (1)
Second half life of this reaction will be . So, expression for this will be as follows.
=
...(2)
where is the final concentration that is,
here and
is the initial concentration.
Hence, putting these values into equation (2) formula as follows.
=
= ...... (3)
Now, dividing equation (3) by equation (1) as follows.
=
= 3
or, = 3
Thus, we can conclude that one would expect the second half-life of this reaction to be three times the first half-life of this reaction.