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Gwar [14]
3 years ago
15

Which expression is equivalent to 3(2x−4)+4x−2

Mathematics
2 answers:
Readme [11.4K]3 years ago
5 0
I hope this helps you



3.2x-3.4+4x-2


6x-12+4x-2


10x-14
Oksana_A [137]3 years ago
5 0
Simple...

you have: 3(2x-4)+4x-2

simplify-->>>

3(2x-4)+4x-2

Get rid of the parentheses....(distribute the 3)

3*2x=6x

and

3*-4=-12

6x-12+4x-2

Now add your apples and oranges--->>>

10x-14

Thus, your answer.
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For each ordered pair (x, y), determine whether it is a solution to the inequality 4x+8y5-8. Is it a solution? Yes No O (6, – 4)
avanturin [10]

Given inequality is:

4x+8y\leq-8

Now for (6,-4), Put x=6 nd y=-4 in given inequality:

\begin{gathered} 4(6)+8(-4)\leq-8 \\ 24-32\leq-8 \\ -8\leq-8 \end{gathered}

So for (6,-4) this inequality is true.

For (-2,-3) put x=-2 and y=-3 in given inequality:

\begin{gathered} 4(-2)+8(-3)\leq-8 \\ -8-24\leq-8 \\ -32\leq-8 \end{gathered}

As -32 is less than -8 then this condition is also true.

simillarly you can check for other options also.

For (-7,5) Put x=-7 and y=5 in given inequality:

\begin{gathered} 4(-7)+8(5)\leq-8 \\ -28+40\leq-8 \\ 12\leq-8 \end{gathered}

As 12 is grater than -8 so this condition is false.

And for (-6,0) put x=-6 and y=0 in given inequality:

\begin{gathered} 4(-6)+8(0)\leq-8 \\ -24\leq-8 \end{gathered}

As -24 is less than -8 so it is true.

4 0
1 year ago
3. Kai sold 3x +5 textbooks in August and 2in September. What
Fittoniya [83]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
What are the possible numbers of positive real, negative real, and complex zeros of f(x) = 8x^4 + 13x^3 − 11x^2 + x + 9?
alina1380 [7]
<span> By Descartes' Rules of Signs, you need to find the sign changes for f(x) and f(-x) [Positive and Negative Case - respectively]

f(x) = 8x^4 + 13x³ - 11x² + x + 9

Since there are two sign changes between terms, we can show that there are possibly 2 positive roots.



f(-x) = 8x^4 - 13x³ - 11x² - x + 9

For the negative case, you let x = -x. Then, we have 8x^4 - 13x³ - 11x² - x + 9. There are 2 possible negative roots since there are 2 sign changes. Hence, the possible choice is:

 

Positive Real: 2 or 0
Negative Real: 2 or 0
Complex: 4, 2 or 0
</span>

i know i am late and i hope you still need the help ! :D

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