Find the value or values of y in the quadratic equation y2 + 4y + 4 = 7

Mathematics

2 answers:

Tema [17]3 years ago

6 0

Hello,

y²+4y+4=7
==>(y+2)²-7=0
==>(y+2-√7)(y+2+√7)=0
==>y=-2+√7 or y=-2-√7

mafiozo [28]3 years ago

4 0

Hey man this is how i did it. I think it's right. Not sure

y²+4y+4=7

Then (y+2)²-7=0

Separate (y+2-√7)(y+2+√7)=0

Simplify y=-2+√7 or y=-2-√7

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Which equations represent the line that is perpendicular to the line 5x − 2y = −6 and passes through the point (5, −4)? Select t

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Step-by-step explanation:

Two lines are perpendicular if the first line has a slope of $m$ and the second line has a slope of $\frac{1}{-m}$ .

With this information, we first need to figure out what the slope of the line is that we're given, and then we can determine what the slope of the line we're trying to find is:

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We now know that $m = \frac{5}{2}$ for the first line, which means that the slope of the second line is $m = \frac{-2}{5}$ . With this, we have the following equation for our new line: