Question

Copper(II) fluoride contains 37.42% F by mass. Calculate the mass of fluorine (in g) in 55.5 g of copper(II) fluoride.

Answer 1

Answer:

There are 20.8 g of fluorine in 55.5 g of copper (II) fluoride

Explanation:

x % by mass of a species in a specimen means there are x g of the species in total 100 g of a specimen

37.42 % F by mass means 100 g of copper (II) fluoride contains 37.42 g of F.

So, 100 g of copper (II) fluoride contains 37.42 g of F

55.5 g of copper (II) fluoride contains $\frac{37.42\times 55.5}{100}$g of F or 20.8 g of F

Hence there are 20.8 g of fluorine in 55.5 g of copper (II) fluoride.