How many moles are in 4.24kg of Na2CO3?
1 answer:
Data:
4.24 Kg converting (grams) → 4240 g
Molar Mass of
Na = 2*23 = 46 amu
C = 1*12 = 12 amu
O = 3*16 = 48 amu
-------------------------
Molar Mass of = 46 + 12 + 48 = 106 g/mol
If:
106 g → 1 mol
4240 g → y
Solving: <span>Rule of three (directly proportional)
</span>
multiply cross
106*y = 4240*1
106y = 4240
Answer:
<span>B. 40.0 moles</span>
4.24 Kg converting (grams) → 4240 g
Molar Mass of
Na = 2*23 = 46 amu
C = 1*12 = 12 amu
O = 3*16 = 48 amu
-------------------------
Molar Mass of
If:
106 g → 1 mol
4240 g → y
Solving: <span>Rule of three (directly proportional)
</span>
multiply cross
106*y = 4240*1
106y = 4240
Answer:
<span>B. 40.0 moles</span>
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Answer:
0.14 moles of Fe₂O₃
Explanation:
Given parameters:
Number of moles of Fe = 0.27moles
Unknown:
Number of moles of Fe₂O₃ = ?
Solution:
To solve this problem, we are going to the work from the known specie to the unknown using their number of moles.
We first obtain the balanced equation of the reaction;
4Fe + 3O₂ → 2Fe₂O₃
The equation above is balanced;
4 moles of Fe produced 2 moles of Fe₂O₃
0.27 moles of Fe will produce = 0.14 moles of Fe₂O₃