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Lubov Fominskaja [6]
3 years ago
6

How many moles are in 4.24kg of Na2CO3?

Chemistry
1 answer:
netineya [11]3 years ago
7 0
Data:
4.24 Kg converting (grams) → 4240 g

Molar Mass of Na_{2} CO_{3}
Na = 2*23 = 46 amu
C = 1*12 = 12 amu
O = 3*16 = 48 amu
-------------------------
Molar Mass of Na_{2} CO_{3} = 46 + 12 + 48 = 106 g/mol

If:

106 g → 1 mol
4240 g → y

Solving: <span>Rule of three (directly proportional)
</span>\frac{106}{4240} = \frac{1}{y}
multiply cross
106*y = 4240*1
106y = 4240
y =  \frac{4240}{106}
\boxed{\boxed{y = 40\:moles}}\end{array}}\qquad\quad\checkmark

Answer:
<span>B. 40.0 moles</span>
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Solution:- Given commercial sample of ammonia is 28% by mass. Let's say we have 100 grams of the sample. Then mass of ammonia would be 28 grams.

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Explanation:

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