All categories

2 years ago

Algebra 2 help? Will give brainliest

Mathematics

1 answer:

Sergio [31]2 years ago

6 0

Step-by-step explanation:

if |A|≥B then

A≥B or A≤-B

4x-10≥14 or 4x≤-14

solve 4x-10≥14

add 20 on both sides

4x≥10+14

4x≥24

divide by 4 on both ends

x≥24/4

x≥6

now solve

4x-10≤-14

add 10 on both sides

4x≤-14+10

4x≤-4

divide both sides by 4

x≤-1

(-∞,-1] U [6,∞)

You might be interested in

Tri-County Utilities, Inc., supplies natural gas to customers in a three-county area. The company purchases natural gas from two

Sav [38]

Answer:

The network model is attached.

Step-by-step explanation:

Total Demand from each Gas Company are:

Southern Gas, 500 units;

Northwest Gas, 400 units.

Total Supplies to each County are:

Hamilton County, 400 units;

Butler County, 200 units;

Clermont County, 300 units.

The distribution costs per unit (in thousands of dollars) are as follows

-----------Hamilton-- Butler-- Clermont

Southern Gas--- 10 ---20--- 15

Northwest Gas ----12 ----15---- 18

The network representation of these information is given in the attachment.

3 0

3 years ago

Which of the following are coefficient

malfutka [58]

Answer:

2 and -3

Step-by-step explanation:

because a coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression (e.g. 4 in 4x).

so in 2x-3y+5, 2 and -3 are the coefficients.

4 0

2 years ago

38 plus what equals 99

mote1985 [20]

To figure that out you could do 99 minus 38, which would lead you to your answer 61.

7 0

3 years ago

B<br> D<br> A<br> C<br> side AC is extended to point D with m

Minchanka [31]

Answer:

im so confused

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish

Anna007 [38]

Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or $\frac{x}{y}=\frac{333}{444}$

⇒ $\frac{x}{y}=\frac{3}{4}$

⇒ y = $\frac{4x}{3}$ --------(1)

Similarly x' : y' = 333 : 444

⇒ $\frac{x'}{y'}=\frac{333}{444}$

⇒ $\frac{x'}{y'}=\frac{3}{4}$

⇒ x' = $\frac{3y'}{4}$ ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

$\frac{x+y}{x'+y'}=\frac{464646}{555}$

Now we replace the values of x and y' from equation (1) and equation (2)

$\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}$

$\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}$

$\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}$

$\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}$

$\frac{x}{y'}=\frac{232323}{370}$

$\frac{y'}{x}=\frac{370}{232323}$

$\frac{y'}{x}=\frac{10}{6279}$

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

4 0

3 years ago