Algebra 2 help? Will give brainliest
1 answer:
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To show that the ratio is not constant for the function
we only need to evaluate this function at 2 points and then show that the ratio is not the same for those two points. Note that here
represents
.
To find the counter examples here, I will use the values and
. For
, the equation tells us that the output is
. For this value of
the point is point is
. The ratio
. For the
,
. For this value of
the point is
. The ratio
. Clearly this ratio is not constant for all ordered pairs.
Answer:
Option 2
Step-by-step explanation:
First, find the slope of the line of the graph using the points given as (5, -3) and (13, -9):
Any of the triangle in the options given, whose opp side has the same slope value of -¾, is the triangle we are looking for.
Option 1: slope between the points (0, 2) and (3, -2).
Option 2: slope between the point (-7, 6) and (-3, 3).
Option 2 has the same slope as the one given in the graph. This is the answer.
Option 3: slope between the points (5, -1) and (2, -5).
Option 4: slope between the points (2, -7) and (6, -4).
The answer is Option 2