Solve 2x2 + x − 4 = 0 using completing the square

1 answer:

6 0

$2x^2+x-4=0$
$x^2+\dfrac12x-2=0$
$x^2+\dfrac12x+\dfrac1{16}-\dfrac{33}{16}=0$
$\left(x+\dfrac14\right)^2=\dfrac{33}{16}$
$x+\dfrac14=\pm\dfrac{\sqrt{33}}4$
$x=\dfrac{-1\pm\sqrt{33}}4$

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