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Mnenie [13.5K]
4 years ago
7

The compound Lead(II) Nitrate reacts with potassium Iodide.

Chemistry
1 answer:
marshall27 [118]4 years ago
7 0

Answer:

a) Pb(NO3)2 + 2KI ⇒ PbI2 + 2K(NO3)

ion that form the precipitate = Pb2+ and I-

Spectator ions = NO3. and K+

b) Pb 2+ + 2 I- ⇒ PbI2

Explanation:

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Water (2150 gg ) is heated until it just begins to boil. If the water absorbs 5.91×105 JJ of heat in the process, what was the i
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Answer:

Initial temperature of water was 34,3°C

Explanation:

The heat absorbed in the process (Q) can be written as:

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Where the heat is 5,91x10⁵J, m is mass of water (2150g), c is specific heat of water (4,184J/g°C). And ΔT is change in temperature (100°C - x). Replacing:

5,91x10⁵J = 2150g×4,184J/g°C×(100°C - x)

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34,3°C = x

Thus, <em>initial temperature of water was 34,3°C</em>

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Answer:

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