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Mnenie [13.5K]
4 years ago
7

The compound Lead(II) Nitrate reacts with potassium Iodide.

Chemistry
1 answer:
marshall27 [118]4 years ago
7 0

Answer:

a) Pb(NO3)2 + 2KI ⇒ PbI2 + 2K(NO3)

ion that form the precipitate = Pb2+ and I-

Spectator ions = NO3. and K+

b) Pb 2+ + 2 I- ⇒ PbI2

Explanation:

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