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IrinaVladis [17]
4 years ago
10

Horizontal lines that represent different climate zones are called

Chemistry
1 answer:
Neporo4naja [7]4 years ago
3 0

Answer:

Horizontal lines that represent different climate zones are called latitude.

Explanation:

Latitude is the distance that exists between a point on the Earth's surface to the equator, counted by the degrees of its meridian. That is, it is the distance, measured in degrees, that exists between any parallel and the line of the Equator. The latitude of a point is measured to the North or South of the zero parallel and its value can vary between 0 ° from the equator to 90 ° N from the North pole or 90 ° from the South pole.

Climate is related to latitude because it sets the amount of solar energy that a given region or place receives. Places located at high latitudes (far from the Ecuador) receive less sunlight than places located at low latitudes (near the Equator). Thus, cities distant from the equator and close to the poles have a cold climate, while at low altitudes there are high temperatures and a hot or tropical climate.

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True or False: <br><br> All stars are the same color.
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A decorative "ice" sculpture is carved from dry ice (solid CO2) and held at its sublimation point of –78.5°C. Consider the proce
Leno4ka [110]

Answer:

The answers to the questions are;

a. The entropy of sublimation for carbon dioxide (the system) is  

134.07 J/Kmol.

b. The entropy of the universe for this reversible process is 376 J/K.

Explanation:

Entropy of sublimation is the entropy change experienced following the transformation of a mole of solid to vapor at  the temperature where the sublimation is taking place

a. We note that the mass of the solid CO₂ = 389 g

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Number of moles of CO₂ in the sculpture = Mass/(Molar mass)

= (389 g)/(44.01 g/mol) = 8.84 Moles

Entropy of sublimation is given by

ΔS_{sublimation} = S_{vapor} - S_{solid} = \frac{\Delta H_{sublimation}}{T}

Where:

ΔH_{sublimation}  = 26.1 KJ/mol

T = Temperature = –78.5°C = ‪194.65‬ K

Therefore the amount of heat required to cause the 389 g of dry ice to sublime =    26.1 KJ/mol  × 8.84 Moles = 230.695 KJ

Therefore the entropy of sublimation = ΔS_{sublimation} = \frac{230.695 KJ}{194.65 K}

= 1.185 KJ/K

= 1185 J/K = 1185/8.84 J/Kmol = 134.07 J/Kmol

b. The entropy of the universe is given by;

ΔS_{universe} = \Delta S_{system} + ΔS_{surrounding}  

If the heat absorbed by the system is the same as the heat given off by the surrounding, then we have;

ΔS_{universe} = \frac{Q}{ T_{system}}  -\frac{Q}{T_{surrounding}}  

                =1.185 KJ/K - -\frac{230.695 KJ}{285.15K} = 1.185 KJ/K - 0.809 KJ/K = 0.376 KJ/K

= 376 J/K.

7 0
3 years ago
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